The problem asks us to find the speed of a train in kilometers per hour (km/h), given the distance it travels in meters (m) and the time taken in seconds (s).
First, calculate the speed in meters per second (m/s) using the formula:
Speed = \(\frac{Distance}{Time}\)
Given:
Calculation:
Speed = \(\frac{45 \text{ m}}{3 \text{ s}}\) = 15 m/s
To convert speed from meters per second (m/s) to kilometers per hour (km/h), we use the conversion factor \(\frac{18}{5}\). This factor comes from:
Now, convert the calculated speed:
Speed (km/h) = Speed (m/s) \(\times\) \(\frac{18}{5}\)
Speed (km/h) = 15 \(\times\) \(\frac{18}{5}\)
Speed (km/h) = 3 \(\times\) 18
Speed (km/h) = 54 km/h
The speed of the train is 54 km/h. This corresponds to Option D.
A boy goes to school at a speed of 5 km/hr. He returns at a speed of 14 km/hr. He takes a total of 8 hours for both going to school and returning. The distance (in km) between his home and school is:
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A train travelling at a speed of 72 km/hr crosses a post in 20 seconds. If it crosses another train travelling at a speed of 54 km/hr in the same direction in 1 minute 45 seconds, then the difference in length between the two trains is
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