A light bulb working on a 18 V battery draws a current of 3 A. What will be the resistance of the bulb?
6 Ω
Using Ohm's law,
\(V=IR\)
Hence the resistance is
\(R= rac{V}{I}\)
Given \(V=18\,V\) and \(I=3\,A\),
\(R= rac{18}{3}=6\,\Omega\)
Therefore, the resistance of the bulb is \(6\,\Omega\).
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