This problem requires calculating the total electrical energy consumed by a lamp over a specific period.
Given:
Step 1: Convert Power to Kilowatts (kW)
Energy is typically measured in kilowatt-hours (kWh), often called 'units'. First, convert the power from Watts (W) to Kilowatts (kW).
$ P_{\text{kW}} = \frac{P_{\text{W}}}{1000} $
$ P_{\text{kW}} = \frac{60 \text{ W}}{1000} = 0.06 \text{ kW} $
Step 2: Calculate Daily Energy Consumption
The energy consumed daily is the product of the power in kW and the daily usage time in hours.
$ \text{Energy}_{\text{daily}} = P_{\text{kW}} \times t_{daily} $
$ \text{Energy}_{\text{daily}} = 0.06 \text{ kW} \times 5 \text{ hours} = 0.3 \text{ kWh} $
So, the lamp consumes 0.3 units per day.
Step 3: Calculate Total Energy Consumption for 30 Days
Multiply the daily energy consumption by the total number of days.
$ \text{Total Energy} = \text{Energy}_{\text{daily}} \times D $
$ \text{Total Energy} = 0.3 \text{ kWh/day} \times 30 \text{ days} = 9 \text{ kWh} $
The total energy consumed is 9 units (kWh).
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