All Exams Test series for 1 year @ ₹349 only
Question

A fraction when added to 7/3 gives 4. What is the fraction?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is \(1\frac{2}{3}\)

Finding the Unknown Fraction: Solving the Equation

The problem asks us to find a fraction that, when added to \( \frac{7}{3} \), results in the number 4. We can represent the unknown fraction with a variable, let's say \( x \). The problem can then be translated into a simple algebraic equation:

\( x + \frac{7}{3} = 4 \)

Our goal is to isolate the variable \( x \) on one side of the equation to find its value. To do this, we need to eliminate the term \( \frac{7}{3} \) from the left side. We can achieve this by subtracting \( \frac{7}{3} \) from both sides of the equation. Remember, whatever operation you perform on one side of an equation, you must perform the same operation on the other side to maintain equality.

\( x = 4 - \frac{7}{3} \)

Now, we need to perform the subtraction of a whole number and a fraction. To subtract a fraction from a whole number, we first need to express the whole number as a fraction with the same denominator as the fraction being subtracted. The denominator of \( \frac{7}{3} \) is 3. So, we need to express 4 as a fraction with a denominator of 3.

We know that any whole number can be written as a fraction with a denominator of 1 (e.g., \( 4 = \frac{4}{1} \)). To change the denominator from 1 to 3, we multiply both the numerator and the denominator by 3:

\( 4 = \frac{4 \times 3}{1 \times 3} = \frac{12}{3} \)

Now substitute this back into our equation:

\( x = \frac{12}{3} - \frac{7}{3} \)

Subtracting fractions with the same denominator is straightforward: subtract the numerators and keep the denominator the same.

\( x = \frac{12 - 7}{3} \)

\( x = \frac{5}{3} \)

So, the unknown fraction is \( \frac{5}{3} \). Now let's look at the options provided and see which one matches \( \frac{5}{3} \).

Checking the Options

We will convert the options to improper fractions or compare them with \( \frac{5}{3} \).

  • Option 1: \( \frac{2}{3} \) - This is not equal to \( \frac{5}{3} \).
  • Option 2: \( \frac{13}{2} \) - This is not equal to \( \frac{5}{3} \).
  • Option 3: \( \frac{-1}{1} = -1 \) - This is not equal to \( \frac{5}{3} \).
  • Option 4: \( 1\frac{2}{3} \) - This is a mixed number. Let's convert it to an improper fraction.

    To convert a mixed number \( a\frac{b}{c} \) to an improper fraction, the formula is \( \frac{(a \times c) + b}{c} \).

    For \( 1\frac{2}{3} \), \( a=1, b=2, c=3 \).

    Improper fraction = \( \frac{(1 \times 3) + 2}{3} = \frac{3 + 2}{3} = \frac{5}{3} \).

    This matches our calculated value for \( x \).

Therefore, the fraction is \( 1\frac{2}{3} \).

Operation Equation
Starting equation \( x + \frac{7}{3} = 4 \)
Subtract \( \frac{7}{3} \) from both sides \( x = 4 - \frac{7}{3} \)
Express 4 as a fraction with denominator 3 \( 4 = \frac{12}{3} \)
Substitute and subtract \( x = \frac{12}{3} - \frac{7}{3} = \frac{5}{3} \)
Convert to mixed number \( \frac{5}{3} = 1\frac{2}{3} \)

Revision Table: Understanding Fractions and Equations

Concept Description Example
Fraction Represents a part of a whole. Written as \( \frac{\text{numerator}}{\text{denominator}} \). \( \frac{3}{4} \) (3 parts out of 4)
Improper Fraction A fraction where the numerator is greater than or equal to the denominator. \( \frac{5}{3} \), \( \frac{7}{7} \)
Mixed Number A combination of a whole number and a proper fraction. \( 1\frac{2}{3} \) (1 whole and 2/3)
Converting Mixed to Improper Fraction Multiply whole number by denominator, add numerator, put over original denominator: \( a\frac{b}{c} = \frac{(a \times c) + b}{c} \) \( 2\frac{1}{4} = \frac{(2 \times 4) + 1}{4} = \frac{9}{4} \)
Solving Linear Equations Use inverse operations to isolate the variable. If \( x + a = b \), then \( x = b - a \).

Additional Information: Working with Fractions in Equations

When solving equations involving fractions, a common strategy is to find a common denominator for all terms. In our case, the denominators were 3 and 1 (for the whole number 4). The least common multiple (LCM) of 3 and 1 is 3. We could have also solved the equation by multiplying every term by the LCM, 3, to clear the denominators:

Original equation: \( x + \frac{7}{3} = 4 \)

Multiply every term by 3:

\( 3 \times (x + \frac{7}{3}) = 3 \times 4 \)

Distribute the 3 on the left side:

\( (3 \times x) + (3 \times \frac{7}{3}) = 12 \)

\( 3x + 7 = 12 \)

Now, this is a two-step linear equation without fractions. Subtract 7 from both sides:

\( 3x = 12 - 7 \)

\( 3x = 5 \)

Divide both sides by 3:

\( x = \frac{5}{3} \)

This method also gives the same result, \( \frac{5}{3} \), which confirms our previous calculation. This demonstrates that there can be multiple valid approaches to solving the same mathematical problem.

Was this answer helpful?

Similar Questions

  1. How many three digit whole numbers are there between 75 and 405?

  2. The weights of 3 boxes are 4, 7 and 10 kilograms. Which of the following CANNOT be the total weight, in kilograms, of any combination of these boxes?

  3. The difference between the place values of ‘4’ and ‘2’ in the number 833749502 is:

  4. \(\frac{1}{{300}}\) written as a recurring decimal is:

  5. Tapas, Avi and Rishi shared a cake. Tapas had 1/2 of it, Rishi had 1/3 of it and Avi had the rest. What was Avi’s share of the cake?

  6. Which of the following is not a triangular number?

  7. Which of the numbers given below is the square root of 15376?

  8. Find a two digit number which is exactly three times the product of its digits.

  9. When 472 pieces of plywood, each 0.23 cm thick, are piled on top of each other, what would be the height of the pile in metre?

  10. If 2/3rd of a pizza costs Rs. 300, then 3/5th of a pizza will cost:


Important Questions from Integers

  1. How many three digit whole numbers are there between 75 and 405?

  2. Find the number of integers between $1$ and $150$ (inclusive) having $7$ as one of the digits but which are not divisible by $7$.

  3. Integers are listed from 700 to 1000. In how many integers is the sum of the digits 10 ?

  4. Using 2, 2, 3, 3, 3 as digits, how many distinct numbers greater than 30000 can be formed ?

  5. Consider the following statements :

    1. The sum of 5 consecutive integers can be 100.

    2 The product of three consecutive natural numbers can be equal to their sum.

    Which of the above statements is/are correct ? 

Need Expert Advice?
Upcoming Exams
RRB NTPC
September 27, 2026
Test Series
RRB ALP img
Railways
RRB ALP 2026 Mock Test series
1035 Tests 1 Tests Free
893 Attempts
4.3(235)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App