What will be the 20th term in the given sequence?
-50, -47, -44, ________
7
The question asks us to find the 20th term of the sequence: -50, -47, -44, ...
First, let's determine the type of sequence. We check the difference between consecutive terms:
Since the difference between consecutive terms is constant (3), this is an arithmetic sequence.
For an arithmetic sequence, we need to know:
The formula to find the $n$-th term ($a_n$) of an arithmetic sequence is:
$$a_n = a_1 + (n-1)d$$Where:
Now, we substitute the values we identified into the formula:
Plugging these into the formula:
$$a_{20} = -50 + (20-1) \times 3$$First, calculate the value inside the parenthesis:
$$a_{20} = -50 + (19) \times 3$$Next, perform the multiplication:
$$a_{20} = -50 + 57$$Finally, perform the addition:
$$a_{20} = 7$$Therefore, the 20th term in the given arithmetic sequence is 7.
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\(\frac{1}{{300}}\) written as a recurring decimal is:
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1. The sum of 5 consecutive integers can be 100.
2 The product of three consecutive natural numbers can be equal to their sum.
Which of the above statements is/are correct ?
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Consider the following statements:
1. The sum of the two digits of the number can be determined only if the product of the two digits is known.
2. The difference between the two digits of the number can be determined.
Which of the above statements is/are correct?