Question
A farmer's land is two adjoining trapezoids: T1 with bases 70 m & 50 m, height 20 m; T2 with bases 50 m & 30 m, height 15 m. Land costs ₹60/m^2. What is the total land cost?
This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
₹1,08,000
The area of trapezoid T1 with bases 70 m and 50 m, and height 20 m is \(\text{Area}_{T1} = \frac{1}{2}(70+50) \times 20 = \frac{1}{2} \times 120 \times 20 = 1200\) m².
The area of trapezoid T2 with bases 50 m and 30 m, and height 15 m is \(\text{Area}_{T2} = \frac{1}{2}(50+30) \times 15 = \frac{1}{2} \times 80 \times 15 = 600\) m².
The total area is \(1200 + 600 = 1800\) m².
The total land cost is \(1800 \times 60 = 108000\).
Hence, the answer is ₹1,08,000.
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