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Question

A triangular traffic sign has sides measuring 13 m, 14 m, and 15 m. If the cost to paint the sign is ₹5 per square meter, what will be the total expense to paint the entire sign?

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
₹420

Calculating the Expense to Paint a Triangular Traffic Sign

The problem requires calculating the total cost to paint a triangular traffic sign given its side lengths and the cost per square meter.

1. Calculate the Area of the Triangle

The side lengths of the triangle are $a = 13$ m, $b = 14$ m, and $c = 15$ m. We can use Heron's formula to find the area.

  1. Calculate the semi-perimeter ($s$):

    The semi-perimeter is half the sum of the sides.

    $s = \frac{a+b+c}{2} = \frac{13 + 14 + 15}{2} = \frac{42}{2} = 21 \text{ m}$
  2. Apply Heron's Formula:

    Area ($A$) $= \sqrt{s(s-a)(s-b)(s-c)}$

    $A = \sqrt{21(21-13)(21-14)(21-15)}$ $A = \sqrt{21 \times 8 \times 7 \times 6}$ $A = \sqrt{7056}$ $A = 84 \text{ square meters}$

2. Calculate the Total Painting Cost

The cost to paint the sign is ₹5 per square meter. The total area is 84 square meters.

Total Expense = Area $\times$ Cost per square meter

$ \text{Total Expense} = 84 \, \text{m}^2 \times ₹5/\text{m}^2 $ $ \text{Total Expense} = ₹420 $

Therefore, the total expense to paint the entire sign is ₹420.

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