The problem requires calculating the total cost to paint a triangular traffic sign given its side lengths and the cost per square meter.
The side lengths of the triangle are $a = 13$ m, $b = 14$ m, and $c = 15$ m. We can use Heron's formula to find the area.
The semi-perimeter is half the sum of the sides.
$s = \frac{a+b+c}{2} = \frac{13 + 14 + 15}{2} = \frac{42}{2} = 21 \text{ m}$Area ($A$) $= \sqrt{s(s-a)(s-b)(s-c)}$
$A = \sqrt{21(21-13)(21-14)(21-15)}$ $A = \sqrt{21 \times 8 \times 7 \times 6}$ $A = \sqrt{7056}$ $A = 84 \text{ square meters}$The cost to paint the sign is ₹5 per square meter. The total area is 84 square meters.
Total Expense = Area $\times$ Cost per square meter
$ \text{Total Expense} = 84 \, \text{m}^2 \times ₹5/\text{m}^2 $ $ \text{Total Expense} = ₹420 $Therefore, the total expense to paint the entire sign is ₹420.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)