The problem describes a shape formed by arranging 6 regular hexagons around a common center. These hexagons fit together perfectly without any gaps.
The total area of the combined shape is the sum of the areas of the individual regular hexagons that compose it.
The question asks for the ratio of the area of the combined shape to the area of one hexagon.
Ratio = $\frac{\text{Area of Combined Shape}}{\text{Area of One Hexagon}}$
Substituting the areas:
Ratio = $\frac{A_{total}}{A_h} = \frac{6 \times A_h}{A_h}$
Simplifying the expression, the $A_h$ terms cancel out:
Ratio = $\frac{6}{1}$
This means the ratio is 6:1.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)