The task is to find the base and height of a triangular flag given their ratio and the flag's area.
Let the base be $b$ and the height be $h$. Given:
Using the ratio, we can express the base and height in terms of a common factor, $x$. Let $b = 5x$ and $h = 4x$. This maintains the 5:4 ratio.
The area $A$ of a triangle is given by the formula $A = \frac{1}{2} \times b \times h$. Substitute the expressions for $b$ and $h$, and the given area:
$160 \text{ cm}^2 = \frac{1}{2} \times (5x) \times (4x)$
Simplify the equation:
$160 = \frac{1}{2} \times 20x^2$
$160 = 10x^2$
Solve for $x^2$:
$x^2 = \frac{160}{10}$
$x^2 = 16$
Solve for $x$. Since length must be positive, we take the positive square root:
$x = \sqrt{16}$
$x = 4$
Substitute the value $x=4$ back into the expressions for base and height:
Confirm the calculated dimensions meet the problem's conditions:
Thus, the base is 20 cm and the height is 16 cm.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)