A cyclist travels from the kilometer stone marked 52 to the stone marked 79. How far has the cyclist traveled?
27 kilometers
To determine how far the cyclist has traveled, we need to consider the kilometer stones mentioned in the question.
- \(52\) km to \(79\) km means that the cyclist travels from the marker at the 52nd kilometer to the marker at the 79th kilometer.
- To find the distance traveled, subtract the starting kilometer marker from the ending kilometer marker:
\(79 - 52\)
- Performing the subtraction:
\(79 - 52 = 27\)
- The distance traveled by the cyclist is 27 kilometers.
Let's examine the options provided:
- 27 kilometers - This matches our calculated distance.
- 31 kilometers - This is incorrect, as the subtraction does not result in this value.
- 131 kilometers - This is incorrect and clearly does not align with the context of the distance between kilometer stones.
- 52 kilometers - This is incorrect, as it represents the starting position, not the distance traveled.
Therefore, the correct answer is 27 kilometers.
Similar Questions
During routine workshop maintenance, 80 liters of used engine oil are collected. If each disposal drum has a marked capacity of 25 liters and regulations require drums to be filled to only 80 percent for safe transport, how many drums are required?
If 5 identical components weigh 20 kg, what is the weight of one component?
A rod of length 2 m is cut into 1/4m pieces. How many pieces are obtained?
- What is the value of $|3(1) - 6|$?
Important Questions from Simplification
The value of {5 - 5 ÷ (10 - 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
What should come in place of the question mark (?) in the following question?
[((16 ÷ 4) × 4) ÷ 4] = ?
Simplify the following expression.
\(\frac{{6\frac{1}{2} + 2\frac{5}{7} \times \frac{{14}}{{19}} - \frac{1}{2} \div 2\ of\frac{1}{4}}}{{11 \times 12 \div 12 + 12}}\)
The value of \(\left( {\frac{7}{5} \div \frac{7}{{10}}of\frac{3}{4}} \right) \div \frac{4}{9} + \left( {\frac{7}{{16}} \div 10\frac{1}{2} \times 7\frac{1}{5}} \right) \times \frac{5}{{12}} \) is:
The value of \(\left( {{1 \over 2}} \right)\) [{–2(12 + 2)}10] is:
