There are 5 tasks and 5 persons. Task-1 cannot be assigned to either person-1 or person-2. Task-2 must be assigned to either person-3 or person-4. Every person is to be assigned one task. In how many ways can the assignment be done?
24
In the question, let the 5 task will be W1, W2, W3, W4 and W5 and 5 people be P1, P2, P3, P4 and P5. It is noted that W1 cannot be assigned to P1 and P2, so it can be done through either P3, P4 or P5. Work 2 must be assigned to either P3 or P4. We see that Work 1 can be given to person P3 and P4, so 2 ways, First work can be done in 3 ways by 3 person while third work can be done by 4 persons in 4 ways, so possibility will be 2*3*4 = 24, which is option C.
Important Questions from Simplification
If P = 0.3 × 0.3 + 0.03 × 0.03 - 0.6 × 0.03 and Q = 0.54, then \(\rm \frac{P}{Q}\) is equal to:
The value of \(\left(\frac{1}{2}\right)^{−2} \times\left(\frac{1}{3}\right)^{−2} \times\left(\frac{1}{4}\right)^{−2} \) is
The solution of the equation \(\frac{2}{3 x-4}+\frac{2}{2 x-6}=0 \) is:
If \(\rm \sqrt{1225 \times \sqrt{32 \div x}}= 70\) find the value of x.
What will come in the place of question mark (?) in the given expression?
\(\sqrt{21+\sqrt{49}+\sqrt{64}} \space {\%\:of\:5000}=?\)
