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Question

Divide \(\frac{(-10x+50)}{(x-5)}\), when \(x \neq 5\)

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
-10

Simplifying the Algebraic Expression

To divide the expression \(\frac{(-10x+50)}{(x-5)}\), we first factor the numerator.

The numerator is \(-10x + 50\). We can factor out a common factor of \(-10\):

\(-10x + 50 = -10(x - 5)\)

Performing the Division

Now substitute the factored numerator back into the original expression:

\(\frac{-10(x - 5)}{(x - 5)}\)

Since it is given that \(x \neq 5\), the term \((x - 5)\) is non-zero. Therefore, we can cancel the common factor \((x - 5)\) from the numerator and the denominator.

\(\frac{-10\cancel{(x - 5)}}{\cancel{(x - 5)}} = -10\)

The result of the division is \(-10\).

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