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Question

What is the value of $|3(1) - 6|$?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
3

Evaluating the Absolute Value Expression $|3(1) - 6|$

This problem requires simplifying a mathematical expression involving absolute value. The absolute value of a number represents its distance from zero, which is always a non-negative value.

1. Simplify Inside the Absolute Value

First, perform the calculation within the absolute value bars:

Expression: $3(1) - 6$

  1. Multiply: $3 \times 1 = 3$
  2. Subtract: $3 - 6 = -3$

The expression simplifies to $\left| -3 \right|$.

2. Determine the Absolute Value

Next, find the absolute value of the result (-3). The absolute value function, denoted by $|x|$, returns the non-negative value of $x$.

Absolute Value: $\left| -3 \right| = 3$

Final Value

Therefore, the value of the expression $|3(1) - 6|$ is 3.

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Important Questions from Simplification

  1. The value of {5 - 5 ÷ (10 - 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:

  2. What should come in place of the question mark (?) in the following question?

    [((16 ÷ 4) × 4) ÷ 4] = ?

  3. Simplify the following expression.

    \(\frac{{6\frac{1}{2} + 2\frac{5}{7} \times \frac{{14}}{{19}} - \frac{1}{2} \div 2\ of\frac{1}{4}}}{{11 \times 12 \div 12 + 12}}\)

  4. The value of \(\left( {\frac{7}{5} \div \frac{7}{{10}}of\frac{3}{4}} \right) \div \frac{4}{9} + \left( {\frac{7}{{16}} \div 10\frac{1}{2} \times 7\frac{1}{5}} \right) \times \frac{5}{{12}} \)  is:

  5. The value of \(\left( {{1 \over 2}} \right)\) [{–2(12 + 2)}10] is:

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