If 5 identical components weigh 20 kg, what is the weight of one component?
4 kg
The five components are identical, so the total weight is shared equally among them and the weight of one is the total divided by the count.
This is a direct division of a whole into equal parts.
Weight of one component \(=\dfrac{20\ \text{kg}}{5}=4\ \text{kg}\).
As a check, multiplying back gives \(5\times4=20\ \text{kg}\), which matches the given total.
Options such as 2 kg or 10 kg come from dividing or multiplying by the wrong number, and 5 kg would need a total of 25 kg.
Hence, the answer is 4 kg.
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Important Questions from Simplification
The value of {5 - 5 ÷ (10 - 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:
What should come in place of the question mark (?) in the following question?
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The value of \(\left( {\frac{7}{5} \div \frac{7}{{10}}of\frac{3}{4}} \right) \div \frac{4}{9} + \left( {\frac{7}{{16}} \div 10\frac{1}{2} \times 7\frac{1}{5}} \right) \times \frac{5}{{12}} \) is:
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