The cyclist's journey forms a path that can be visualized geometrically.
This path creates a right-angled triangle, where:
We use the Pythagorean theorem to find the length of the hypotenuse ($c$), given the lengths of the two legs ($a$ and $b$). The theorem states:
$a^2 + b^2 = c^2$
Here, $a = 3$ km and $b = 4$ km.
$3^2 + 4^2 = c^2$
$9 + 16 = c^2$
$25 = c^2$
$c = \sqrt{25}$
$c = 5$
Therefore, the shortest distance between point $X$ and $Y$ is 5 km.
The rectangle represents a set of calculations that are common across all the given equations. Identify the calculations involved and solve the fourth equation on the same basis:
$7 \blacksquare 4 = 27/4$
$6 \blacksquare 1 = 5$
$4 \blacksquare 3 = 11/3$
$a \blacksquare b = ?$