There are five persons A, G, M, J and D. Every person has to select one item each from a box containing items numbered from 1 to 5. A and J selected items 5 and 2 respectively. G cannot select item 3, while M cannot select item 3 or 5.
Which item can G select?
This problem requires identifying the possible item selections for person G given specific constraints on item allocation among five people.
Identify Assigned Items:
Item 5 is assigned to A.
Item 2 is assigned to J.
Items assigned so far: $\{2, 5\}$.
Determine Remaining Items:
The initial set of items is $\{1, 2, 3, 4, 5\}$.
After A and J select their items, the remaining available items are $\{1, 3, 4\}$.
Analyze G's Possible Selections:
G is restricted from selecting item 3.
From the remaining items $\{1, 3, 4\}$, G can only choose between item 1 and item 4.
Possible items for G: $\{1, 4\}$.
Verify Feasibility for G's Options:
We need to confirm if assignments are possible for the remaining persons (M and D) regardless of whether G selects 1 or 4.
Scenario 1: G selects item 1.
Items remaining for M and D: $\{3, 4\}$.
Constraint: M cannot select item 3. M must select item 4.
This leaves item 3 for D. (Valid assignment: A=5, J=2, G=1, M=4, D=3).
Scenario 2: G selects item 4.
Items remaining for M and D: $\{1, 3\}$.
Constraint: M cannot select item 3. M must select item 1.
This leaves item 3 for D. (Valid assignment: A=5, J=2, G=4, M=1, D=3).
Since both scenarios lead to a valid distribution of items, G can indeed select either item 1 or item 4.
G can select either Item 1 or Item 4.
The rectangle represents a set of calculations that are common across all the given equations. Identify the calculations involved and solve the fourth equation on the same basis:
$7 \blacksquare 4 = 27/4$
$6 \blacksquare 1 = 5$
$4 \blacksquare 3 = 11/3$
$a \blacksquare b = ?$
The rectangle represents a set of calculations that are common across all the given equations. Identify the calculations involved and solve the fourth equation on the same basis:
$7 \blacksquare 4 = 27/4$
$6 \blacksquare 1 = 5$
$4 \blacksquare 3 = 11/3$
$a \blacksquare b = ?$