Question
Huma's mother gave Huma 4 baskets of blueberries each labelled A, B, C, D. Each berry weighs 5 g, except for the basket, which has all rotten berries, where each berry has a weight of 3 g. Huma took out 1, 2, 3 and 4 berries from the baskets A, B, C and D respectively and weighed them to be 44 grams. Which basket has the rotten berries?
This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper PDF (31-Jan-2021) (Shift 1)
The correct answer is
Basket C
Blueberry Weight Puzzle Analysis
Problem Setup:
- Four baskets (A, B, C, D) contain blueberries.
- Normal berries weigh 5g each.
- Rotten berries weigh 3g each.
- Huma samples berries: 1 from A, 2 from B, 3 from C, 4 from D.
- The total weight of sampled berries is 44g.
- The objective is to identify the basket containing the rotten berries.
Calculating Rotten Berries
Step 1: Calculate Expected Weight (All Normal Berries)
- If all berries were normal (5g):
- Basket A: $1 \times 5g = 5g$
- Basket B: $2 \times 5g = 10g$
- Basket C: $3 \times 5g = 15g$
- Basket D: $4 \times 5g = 20g$
- Total expected weight = $5g + 10g + 15g + 20g = 50g$.
Step 2: Determine Total Weight Difference
- The difference between the expected weight and the actual measured weight reveals the impact of the rotten berries.
- Total weight difference = Expected weight - Actual weight
- Total weight difference = $50g - 44g = 6g$.
Step 3: Calculate Weight Difference per Rotten Berry
- Each rotten berry weighs less than a normal berry.
- Weight difference per berry = Normal berry weight - Rotten berry weight
- Weight difference per berry = $5g - 3g = 2g$.
Step 4: Find the Number of Rotten Berries
- Divide the total weight difference by the weight difference per berry.
- Number of rotten berries = Total weight difference / Weight difference per berry
- Number of rotten berries = $6g / 2g = 3$.
Identifying the Rotten Berry Basket
Step 5: Match Rotten Berries to Basket Sample Size
- Huma took 1 berry from Basket A, 2 from B, 3 from C, and 4 from D.
- Since we calculated that there are 3 rotten berries, and Huma took exactly 3 berries from Basket C, this implies Basket C contains the rotten berries.
Final Answer Derivation:
The calculation shows 3 rotten berries. Huma took 3 berries from Basket C. Therefore, Basket C is the one with rotten berries.
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