A coil has 100 turns. If the magnetic flux linked with each turn changes by 0.05 Wb in 1 s, the induced emf is:
5 V
By Faraday's law, the induced emf in a coil of N turns is \(e = N\frac{\Delta\Phi}{\Delta t}\) (in magnitude).
Given: N = 100, ΔΦ = 0.05 Wb per turn and Δt = 1 s.
\(e = 100 \times \frac{0.05}{1} = 5\ \text{V}\).
Hence, the answer is 5 V.
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