A circular coil of radius R having N number of turns carries a steady current I. The magnetic induction at the centre of the coil is 0.1 tesla. If the number of turns is doubled and the radius is halved, which one of the following will be the correct value for the magnetic induction at the centre of the coil?
0.4 tesla
The question asks us to find the new magnetic induction at the center of a circular coil when its physical parameters are changed. We are given the initial magnetic induction and the changes in the number of turns and radius.
The magnetic induction (or magnetic field strength) at the center of a circular coil carrying a steady current is given by the formula:
\( B = \frac{\mu_0 N I}{2R} \)
Where:
From this formula, we can see that the magnetic field \( B \) is directly proportional to the number of turns \( N \) and the current \( I \), and inversely proportional to the radius \( R \).
We are given the initial conditions for the circular coil:
Using the formula, the initial magnetic induction can be written as:
\( 0.1 = \frac{\mu_0 N I}{2R} \)
Let's call this Equation (1).
The question states that the coil is changed as follows:
Now, let's use the formula for magnetic induction with the new parameters \( N' \), \( I' \), and \( R' \) to find the new magnetic induction \( B' \) at the center of the coil:
\( B' = \frac{\mu_0 N' I'}{2R'} \)
Substitute the new values: \( N' = 2N \), \( I' = I \), and \( R' = \frac{R}{2} \):
\( B' = \frac{\mu_0 (2N) (I)}{2(\frac{R}{2})} \)
Let's simplify the expression:
\( B' = \frac{\mu_0 2N I}{R} \)
We can rearrange this expression to relate it to the initial magnetic induction formula:
\( B' = 2 \times \frac{\mu_0 N I}{R} \)
To make it look exactly like Equation (1), we can rewrite it as:
\( B' = 4 \times \frac{\mu_0 N I}{2R} \)
Notice that the term \( \frac{\mu_0 N I}{2R} \) is exactly the initial magnetic induction \( B \) from Equation (1). So, we can substitute \( 0.1 \) tesla for this term:
\( B' = 4 \times (0.1 \text{ T}) \)
\( B' = 0.4 \text{ T} \)
When the number of turns in the circular coil is doubled and the radius is halved, while keeping the current steady, the magnetic induction at the center of the coil becomes 0.4 tesla.
| Parameter | Initial Value | Change | New Value | Effect on B (from formula \( B \propto N/R \)) |
|---|---|---|---|---|
| Number of Turns (N) | \( N \) | Doubled | \( N' = 2N \) | B becomes \( 2 \times \) original B |
| Radius (R) | \( R \) | Halved | \( R' = R/2 \) | B becomes \( 1/(1/2) = 2 \times \) original B |
| Current (I) | \( I \) | Steady | \( I' = I \) | No change in B due to current |
Since \( B \propto N/R \), the combined effect is that the new magnetic field \( B' \) will be proportional to \( (2N) / (R/2) \), which simplifies to \( 4N/R \). This is 4 times the original proportionality \( N/R \). Therefore, the new magnetic field is 4 times the original magnetic field.
\( B_{new} = 4 \times B_{original} \)
\( B_{new} = 4 \times 0.1 \text{ T} = 0.4 \text{ T} \)
| Concept | Formula | Key Factors |
|---|---|---|
| Magnetic field at coil center | \( B = \frac{\mu_0 N I}{2R} \) | Number of turns (N), Current (I), Radius (R) |
| Proportionality | \( B \propto \frac{NI}{R} \) | Directly proportional to N and I, Inversely proportional to R |
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