A can do a piece of work in 40 days. He works at it for 10 days, and then B alone finishes the remaining work in 45 days. In how many days will A and B working together finish 75% of the same work?
18
A's rate is 1/40 per day, so in 10 days A finishes 1/4 of the work, leaving 3/4. B finishes this 3/4 in 45 days, so B alone would take 60 days for the whole work, giving B's rate as 1/60. Combined rate = 1/40 + 1/60 = 1/24 per day, so 75% of the work takes 0.75 × 24 = 18 days.
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