A banner is shaped like a trapezium with bases 5 m and 3 m, and height 4 m. If printing costs ₹250/m^2, what is the total cost?
₹4,000
The area of a trapezium is given by \(\text{Area} = \frac{1}{2}(b_1+b_2) \times h\), where \(b_1 = 5\) m, \(b_2 = 3\) m, and \(h = 4\) m.
Substituting the values, \(\text{Area} = \frac{1}{2}(5+3) \times 4 = \frac{1}{2} \times 8 \times 4 = 16\) m².
The total printing cost is \(16 \times 250 = 4000\).
Hence, the answer is ₹4,000.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)