A and B together can complete a given work in 10 days. C can complete the same work alone in 15 days. In how many days can they complete the work, if all three work together?
6 days
This question asks us to find out how many days it will take for three individuals, A, B, and C, to complete a specific work when they work together. We are given the time taken by A and B together, and the time taken by C alone.
In work and time problems, the key idea is to think about the 'rate' at which work is done. The rate is the amount of work completed per unit of time (in this case, per day). If someone completes a work in 'd' days, their rate is $\frac{1}{d}$ of the work per day.
We are given the following information:
From this, we can find their rates:
| Workers | Time Taken (Days) | Rate per Day (Fraction of Work) |
|---|---|---|
| A and B Together | 10 | $\frac{1}{10}$ |
| C Alone | 15 | $\frac{1}{15}$ |
When A, B, and C work together, their individual rates (or in this case, the combined rate of A+B and the rate of C) add up to give their total combined rate per day.
Combined rate of (A + B + C) per day = (Rate of A + B) + (Rate of C)
Combined rate of (A + B + C) per day = $\frac{1}{10} + \frac{1}{15}$
To add the fractions $\frac{1}{10}$ and $\frac{1}{15}$, we need to find a common denominator. The least common multiple (LCM) of 10 and 15 is 30.
$\frac{1}{10} = \frac{1 \times 3}{10 \times 3} = \frac{3}{30}$
$\frac{1}{15} = \frac{1 \times 2}{15 \times 2} = \frac{2}{30}$
Now, add the fractions:
Combined rate of (A + B + C) per day = $\frac{3}{30} + \frac{2}{30} = \frac{3 + 2}{30} = \frac{5}{30}$
Simplify the fraction:
Combined rate of (A + B + C) per day = $\frac{5}{30} = \frac{1}{6}$ of the work.
If the combined rate of A, B, and C is $\frac{1}{6}$ of the work per day, it means they complete $\frac{1}{6}$ of the work each day. To complete the whole work (which is 1 unit), the time taken is the reciprocal of their combined rate.
Time taken by (A + B + C) together = $\frac{1}{\text{Combined rate per day}}$
Time taken by (A + B + C) together = $\frac{1}{\frac{1}{6}} = 1 \times \frac{6}{1} = 6$ days.
Therefore, A, B, and C can complete the work together in 6 days.
| Concept | Explanation | Formula |
|---|---|---|
| Work Rate | Amount of work done per unit of time. | Rate = $\frac{1}{\text{Time taken}}$ |
| Time Taken | Total time required to complete the work. | Time = $\frac{1}{\text{Rate}}$ |
| Combined Rate | Sum of individual rates when multiple people work together. | Rate$_{total}$ = Rate$_1$ + Rate$_2$ + ... |
Work and time problems often involve calculating rates and combining them. Here are some useful tips:
Mohan can do a piece of work in 10 days and Sohan in 15 days. They started working together, but after 3 days Mohan left the work . What time will Sohan take to finish the work?
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Had been one menless, then the number of days required to do a piece of work would have been one more. If the number of Man. Days required to complete the work is 56, how many workers were there?
A can do a piece of work in 16 hours, B and C can do it in 8 hours while A and C can do it 12 hours. How long will B alone take to do it?