A 104-metre-long train crosses another 94-metre-long train running in the same direction in 16.2 seconds. If the speed of the first train is 61 kmph, what is the speed of the second train in kmph?
17 km/hr
When one train crosses another, the total distance covered is the sum of their lengths: \(104 + 94 = 198\) metres.
This distance is covered in 16.2 seconds at the relative speed, so the relative speed is \(\dfrac{198}{16.2} = 12.222\ldots\) m/s.
Convert to km/h by multiplying by \(\dfrac{18}{5}\): \(12.222\ldots \times \dfrac{18}{5} = 44\) km/h.
The trains run in the same direction, so the relative speed is the difference of the two speeds: \(61 - v = 44\).
Solve for the second train's speed: \(v = 61 - 44 = 17\) km/h.
Hence, the speed of the second train is 17 km/hr.
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Important Questions from Problem on Trains
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is:
