The problem involves calculating the total earnings of a specific group of workers (unskilled) based on their individual wage ratios and the total payment for a job completed by skilled, semi-skilled, and unskilled workers.
Let the daily wages of skilled, semi-skilled, and unskilled workers be $9x$, $5x$, and $4x$ respectively, according to the given ratio 9:5:4.
The total earnings for each category are calculated as follows:
The total payment for the job is the sum of earnings from all categories:
Total Payment = $108x + 70x + 40x = 218x$
We are given that the total payment is ₹13189.
Therefore, $218x = 13189$.
Solving for $x$:
$x = \frac{13189}{218}$
$x = 60.5$
The question asks for the total money earned by 10 unskilled workers.
Total earnings for 10 unskilled workers = $40x$
Substitute the value of $x$:
Total earnings = $40 \times 60.5$
Total earnings = $2420$
The total money earned by 10 unskilled workers is ₹2420.
If the wages for 9 workers for 8 days are ₹2,880, what will be the wages for 15 workers for 9 days at the same rate?
A can complete a work alone in 8 days. B can complete the same work alone in 12 days. C alone complete the same work in 16 days. They complete the work in 3 days with the help of D. If they get Rs.12000 for the work, then how much money does the D get?
If 15 men can complete a work in 16 days by working 8 hours daily, then in how many days will 10 men complete the work by working 12 hours daily?
10 men working 8 hours a day can finish a work in 28 days. In how many days, 8 men working 5 hours a day with complete 50% of that work?
Twenty lamps can be lighted for 6 hr a day for 20 days at a cost of Rs. 100. How much would be the cost of lighting 40 lamps, 8 hr for 12 days?
Six men can complete a job in two days. Four boys can complete the same job in eight days. In how many days would three men and six boys, working together, be able to complete the job?