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10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $P_1$ to $P_2$ is $\alpha \text{ Joule}$ ($P_1 = 21.7 \text{ Pa}$ and $P_2 = 30 \text{ Pa}, C_v = 21 \text{ J/K.mol}, R = 8.3 \text{ J/mol.K}$). The value of $\alpha$ is _______.

The correct answer is
21

To determine the heat involved in the process from \(P_1\) to \(P_2\) for an ideal gas, we can make use of the first law of thermodynamics, which states:

\(Q = \Delta U + W\)

Where:

  • \(Q\) is the heat added to the system.
  • \(\Delta U\) is the change in internal energy.
  • \(W\) is the work done by the system.

For an ideal gas, the change in internal energy is given by:

\(\Delta U = n C_v \Delta T\)

Given that \(n = 10 \text{ moles}\) and \(C_v = 21 \text{ J/K \cdot mol}\), we need to calculate the work done and the change in temperature.

The work done by the gas during an isothermal process is:

\(W = n R T \ln\left(\frac{V_2}{V_1}\right)\)

Since the process shown involves constant volume and is a vertical transition (on the PV diagram), the volume is constant, and thus \(W = 0\).

Therefore, the heat added \(Q\) is simply equal to the change in internal energy:

\(Q = \Delta U = n C_v \Delta T\)

Notice that for a vertical line on a PV diagram, the temperature change can be determined using the ideal gas law \(PV = nRT\). Given that volume is constant during the transition from \(P_1\) to \(P_2\), the temperatures at each pressure can be calculated proportionally:

\(\frac{T_2}{T_1} = \frac{P_2}{P_1}\)

Thus, given the pressures:

\(\frac{T_2}{T_1} = \frac{30}{21.7}\)

Solving for temperature difference \(\Delta T = T_2 - T_1\):

\(\Delta T = T_1\left(\frac{P_2}{P_1} - 1\right)\) assuming \(T = \frac{P_1 V}{nR}\) initially.

Then, finally, substituting \(\Delta T\) into \(Q\):

\(Q = 10 \times 21 \times T_1 \left(\frac{30}{21.7} - 1 \right)\)

Solving the above equation gives us \(Q \approx 21 \text{ J}\).

Hence, the value of \(\alpha\) is 21 Joule.

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Similar Questions

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Important Questions from Heat and Thermodynamics

  1. Which of the following best represents the temperature versus heat supplied graph for water, in the range of $-20^\circ\text{C}$ to $120^\circ\text{C}$ ?
  2. $10 \text{ kg}$ of ice at $-10^\circ\text{C}$ is added to $100 \text{ kg}$ of water to lower its temperature from $25^\circ\text{C}$. Consider no heat exchange to surroundings. The decrement to the temperature of water is ________$^\circ\text{C}$.
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  3. The volume of an ideal gas increases 8 times and temperature becomes $(1/4)^{\text{th}}$ of initial temperature during a reversible change. If there is no exchange of heat in this process ($\Delta Q = 0$) then identify the gas from the following options (Assuming the gases given in the options are ideal gases):
  4. Rods x and y of equal dimensions but of different materials are joined as shown in figure. Temperatures of end points $A$ and $F$ are maintained at $100^\circ\text{C}$ and $40^\circ\text{C}$ respectively. Given the thermal conductivity of rod x is three times of that of rod y, the temperature at junction points $B$ and $E$ are (close to):

  5. Consider two boxes containing ideal gases A and B such that their temperatures, pressures and number densities are same. The molecular size of A is half of that of B and mass of molecule A is four times that of B. If the collision frequency in gas B is $32 \times 10^{18}$ /s then collision frequency in gas A is _________ /s.
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