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Question

(0.1 2- 0.025 2) ÷ (0.1 - 0.025) = ______.

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

0.125

Calculating (0.1<sup>2</sup> - 0.025<sup>2</sup>) ÷ (0.1 - 0.025)

The problem asks us to evaluate the expression: \((0.1^2 - 0.025^2) \div (0.1 - 0.025)\). This expression involves squares and division of decimal numbers.

Let's analyze the structure of the expression. The numerator is in the form of a difference of squares, \(a^2 - b^2\), where \(a = 0.1\) and \(b = 0.025\). The denominator is the difference of the same two numbers, \(a - b\).

We can use the algebraic identity for the difference of squares, which states:

\(a^2 - b^2 = (a - b)(a + b)\)

Using this identity, we can rewrite the numerator of the given expression:

\(0.1^2 - 0.025^2 = (0.1 - 0.025)(0.1 + 0.025)\)

Now substitute this back into the original expression:

\(\frac{0.1^2 - 0.025^2}{0.1 - 0.025} = \frac{(0.1 - 0.025)(0.1 + 0.025)}{0.1 - 0.025}\)

Assuming that the denominator is not zero (which is true since \(0.1 - 0.025 = 0.075 \neq 0\)), we can cancel the term \((0.1 - 0.025)\) from both the numerator and the denominator:

\(\frac{\cancel{(0.1 - 0.025)}(0.1 + 0.025)}{\cancel{(0.1 - 0.025)}} = 0.1 + 0.025\)

Now, we just need to perform the addition:

\(0.1 + 0.025\)

To add these decimal numbers, we can align the decimal points:

\(\begin{array}{c} \phantom{+} 0.100 \\ + 0.025 \\ \hline \phantom{+} 0.125 \end{array}\)

So, the result of the expression is \(0.125\).

Let's compare this result with the given options:

  • Option 1: 0.325
  • Option 2: 0.125
  • Option 3: 0.625
  • Option 4: 0.25

The calculated value \(0.125\) matches Option 2.

Step-by-Step Calculation Summary

  1. Identify the structure of the expression as a difference of squares divided by the difference of the base numbers.
  2. Recall or apply the difference of squares formula: \(a^2 - b^2 = (a - b)(a + b)\).
  3. Substitute the numbers into the formula: \(0.1^2 - 0.025^2 = (0.1 - 0.025)(0.1 + 0.025)\).
  4. Rewrite the original expression using the factored numerator: \(\frac{(0.1 - 0.025)(0.1 + 0.025)}{0.1 - 0.025}\).
  5. Cancel out the common term \((0.1 - 0.025)\) from the numerator and the denominator.
  6. The expression simplifies to \(0.1 + 0.025\).
  7. Perform the addition: \(0.1 + 0.025 = 0.125\).
  8. Match the result with the provided options.

Revision Table: Key Concepts

Concept Description Formula/Example
Difference of Squares An algebraic factorization pattern for an expression that is the difference between two perfect squares. \(a^2 - b^2 = (a - b)(a + b)\)
Decimal Addition Adding numbers that contain decimal points. Requires aligning the decimal points before adding. \(0.1 + 0.025 = 0.125\)
Algebraic Simplification Reducing an algebraic expression to a simpler form, often by factoring and cancelling common terms. \(\frac{(x-y)(x+y)}{(x-y)} = x+y\) (where \(x \neq y\))

Additional Information: Understanding Difference of Squares

The difference of squares identity, \(a^2 - b^2 = (a - b)(a + b)\), is a fundamental concept in algebra. It is useful for factoring expressions, simplifying fractions like in this problem, and solving equations.

Let's see why the formula \(a^2 - b^2 = (a - b)(a + b)\) works:

Consider the product \((a - b)(a + b)\). Using the distributive property (or FOIL method):

  • First terms: \(a \times a = a^2\)
  • Outer terms: \(a \times b = ab\)
  • Inner terms: \(-b \times a = -ab\)
  • Last terms: \(-b \times b = -b^2\)

Adding these terms together:

\((a - b)(a + b) = a^2 + ab - ab - b^2\)

The terms \(+ab\) and \(-ab\) cancel each other out:

\((a - b)(a + b) = a^2 - b^2\)

This confirms the identity. In our problem, recognizing this pattern allowed us to simplify a complex-looking division into a simple addition.

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