(0.1 2- 0.025 2) ÷ (0.1 - 0.025) = ______.
0.125
The problem asks us to evaluate the expression: \((0.1^2 - 0.025^2) \div (0.1 - 0.025)\). This expression involves squares and division of decimal numbers.
Let's analyze the structure of the expression. The numerator is in the form of a difference of squares, \(a^2 - b^2\), where \(a = 0.1\) and \(b = 0.025\). The denominator is the difference of the same two numbers, \(a - b\).
We can use the algebraic identity for the difference of squares, which states:
\(a^2 - b^2 = (a - b)(a + b)\)
Using this identity, we can rewrite the numerator of the given expression:
\(0.1^2 - 0.025^2 = (0.1 - 0.025)(0.1 + 0.025)\)
Now substitute this back into the original expression:
\(\frac{0.1^2 - 0.025^2}{0.1 - 0.025} = \frac{(0.1 - 0.025)(0.1 + 0.025)}{0.1 - 0.025}\)
Assuming that the denominator is not zero (which is true since \(0.1 - 0.025 = 0.075 \neq 0\)), we can cancel the term \((0.1 - 0.025)\) from both the numerator and the denominator:
\(\frac{\cancel{(0.1 - 0.025)}(0.1 + 0.025)}{\cancel{(0.1 - 0.025)}} = 0.1 + 0.025\)
Now, we just need to perform the addition:
\(0.1 + 0.025\)
To add these decimal numbers, we can align the decimal points:
\(\begin{array}{c} \phantom{+} 0.100 \\ + 0.025 \\ \hline \phantom{+} 0.125 \end{array}\)
So, the result of the expression is \(0.125\).
Let's compare this result with the given options:
The calculated value \(0.125\) matches Option 2.
| Concept | Description | Formula/Example |
|---|---|---|
| Difference of Squares | An algebraic factorization pattern for an expression that is the difference between two perfect squares. | \(a^2 - b^2 = (a - b)(a + b)\) |
| Decimal Addition | Adding numbers that contain decimal points. Requires aligning the decimal points before adding. | \(0.1 + 0.025 = 0.125\) |
| Algebraic Simplification | Reducing an algebraic expression to a simpler form, often by factoring and cancelling common terms. | \(\frac{(x-y)(x+y)}{(x-y)} = x+y\) (where \(x \neq y\)) |
The difference of squares identity, \(a^2 - b^2 = (a - b)(a + b)\), is a fundamental concept in algebra. It is useful for factoring expressions, simplifying fractions like in this problem, and solving equations.
Let's see why the formula \(a^2 - b^2 = (a - b)(a + b)\) works:
Consider the product \((a - b)(a + b)\). Using the distributive property (or FOIL method):
Adding these terms together:
\((a - b)(a + b) = a^2 + ab - ab - b^2\)
The terms \(+ab\) and \(-ab\) cancel each other out:
\((a - b)(a + b) = a^2 - b^2\)
This confirms the identity. In our problem, recognizing this pattern allowed us to simplify a complex-looking division into a simple addition.
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