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Question

The square of 11111 is:

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

123454321

Understanding the Square of 11111

The question asks us to find the square of the number 11111. Squaring a number means multiplying it by itself. So, we need to calculate $11111 \times 11111$.

Direct Calculation Method

We could perform the direct multiplication:

$$ \begin{array}{@{}c@{\,}c@{}c@{}c@{}c@{}c@{}c} & & 1 & 1 & 1 & 1 & 1 \\ \times & & 1 & 1 & 1 & 1 & 1 \\ \hline & & 1 & 1 & 1 & 1 & 1 & & \small{\leftarrow 11111 \times 1} \\ & & 1 & 1 & 1 & 1 & 1 & & \small{\leftarrow 11111 \times 10} \\ & & 1 & 1 & 1 & 1 & 1 & & \small{\leftarrow 11111 \times 100} \\ & & 1 & 1 & 1 & 1 & 1 & & \small{\leftarrow 11111 \times 1000} \\ + & 1 & 1 & 1 & 1 & 1 & & & \small{\leftarrow 11111 \times 10000} \\ \hline & 1 & 2 & 3 & 4 & 5 & 4 & 3 & 2 & 1 \\ \hline \end{array} $$

This direct calculation shows that $11111 \times 11111 = 123454321$. However, this can be a lengthy process, especially with more digits.

Using the Pattern for Squaring Numbers of All Ones

There is a simple and elegant pattern when squaring numbers consisting only of the digit '1'. Let's look at the squares of the first few numbers made of ones:

  • $1^2 = 1$ (1 digit '1' in the number)
  • $11^2 = 121$ (2 digits '1' in the number)
  • $111^2 = 12321$ (3 digits '1' in the number)
  • $1111^2 = 1234321$ (4 digits '1' in the number)

Notice the pattern: the result counts up from 1 to the number of ones in the original number, and then counts back down to 1.

In the number 11111, there are 5 digits of '1'. Following the pattern, the square of 11111 will count up to 5 and then back down to 1:

Count up: 1, 2, 3, 4, 5

Count down from (number of digits - 1): 4, 3, 2, 1

Combining these, we get the result: 123454321.

Comparing with Options

Let's compare our result, 123454321, with the given options:

  • Option 1: 123454321
  • Option 2: 1234321
  • Option 3: 1223311
  • Option 4: 321231

Our calculated value, 123454321, matches Option 1.

Number Number of '1's Square Pattern
1 1 1 1
11 2 121 1, 2, 1
111 3 12321 1, 2, 3, 2, 1
1111 4 1234321 1, 2, 3, 4, 3, 2, 1
11111 5 123454321 1, 2, 3, 4, 5, 4, 3, 2, 1

Conclusion

The square of 11111 is 123454321, which is found using either direct multiplication or by recognising the mathematical pattern associated with squaring numbers composed solely of the digit one.

Revision Table: Squaring Numbers with Ones

Let's summarize the pattern for squaring numbers consisting only of ones:

Number Square Pattern Explained
1 1 One '1', so count up to 1, then down to 1 (just 1).
11 121 Two '1's, so count up to 2 (1, 2), then down to 1 (1). Result: 121.
111 12321 Three '1's, so count up to 3 (1, 2, 3), then down to 1 (2, 1). Result: 12321.
1111 1234321 Four '1's, so count up to 4 (1, 2, 3, 4), then down to 1 (3, 2, 1). Result: 1234321.
11111 123454321 Five '1's, so count up to 5 (1, 2, 3, 4, 5), then down to 1 (4, 3, 2, 1). Result: 123454321.

Additional Information: Mathematical Patterns

Mathematical patterns are sequences or arrangements that follow a specific rule. Recognizing patterns can simplify calculations and help understand mathematical concepts better.

  • Arithmetic Patterns: Involve addition or subtraction (e.g., 2, 4, 6, 8... adding 2 each time).
  • Geometric Patterns: Involve multiplication or division (e.g., 3, 9, 27, 81... multiplying by 3 each time).
  • Number Patterns: Like the one we saw with squaring numbers of ones, these can involve various operations or structural properties of numbers.
  • Visual Patterns: Patterns seen in shapes or diagrams.

The pattern for squaring numbers consisting of ones is a specific type of number pattern. It arises from the distributive property of multiplication and the place value system.

For example, $111^2 = (100 + 10 + 1) \times (100 + 10 + 1)$. When expanded, the structure of the multiplication leads to the central digit being the number of ones, and the digits on either side decreasing symmetrically.

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Important Questions from Surds and Indices

  1. The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\)  is 5 × 10 , where the value of k is :

  2. Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)

  3. If √625 = 25; then√(.00000625/25)is:

    A. 0.0025

    B. 0.001

    C. 0.0001

    D. 0.0005
  4. Find the value of:

    \(\sqrt{150}-\sqrt{54}-\sqrt{24}\)

  5. If \(\sqrt{4624}=68\) , then the value of:

    \(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)

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