A perfect cube is a number that can be obtained by multiplying an integer by itself three times. In mathematical terms, a number '$n$' is a perfect cube if there exists an integer '$k$' such that $n = k^3$.
We need to check which of the given roll numbers is a perfect cube:
Let's find the cube root of 216. We can test small integers:
$1^3 = 1$
$2^3 = 8$
$3^3 = 27$
$4^3 = 64$
$5^3 = 125$
$6^3 = 6 \times 6 \times 6 = 216$
Since $216 = 6^3$, 216 is a perfect cube.
We can check integers around the expected cube root. We know $6^3 = 216$. Let's check $7^3 = 343$. 225 falls between these. Alternatively, we can recognize $225 = 15^2$. It is a perfect square, not a perfect cube.
We know $6^3 = 216$ and $7^3 = 343$. 243 falls between these. Prime factorization of 243 is $3 \times 3 \times 3 \times 3 \times 3 = 3^5$. Since the exponents are not multiples of 3, it's not a perfect cube.
We know $6^3 = 216$ and $7^3 = 343$. 256 falls between these. We can recognize $256 = 16^2$. It is a perfect square, not a perfect cube.
Based on the analysis, only the roll number 216 is a perfect cube ($6^3$).
In the following examples, a number is coded as three digits — representing the remainders when the number is divided by 3, 7, and 11, respectively.
Example 1: $53 \rightarrow 53 \div 3 = 17 \text{ R} 2$, $53 \div 7 = 7 \text{ R } 4$, $53 \div 11 = 4 \text{ R } 9 \rightarrow \text{ Code: } 2, 4, 9$
Example 2: $68 \rightarrow 68 \div 3 = 22 \text{ R} 2$, $68 \div 7 = 9 \text{ R } 5$, $68 \div 11 = 6 \text{ R } 2 \rightarrow \text{ Code: } 2, 5, 2$
By following this method, which is the least number which would have the code - 2, 2, 2?
Which of the following statement is TRUE for Whole Numbers?
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
Which of the above statements is/are correct ?
If the sum S is divided by 8, what is the remainder ?
If the sum S is divided by 60, what is the remainder ?
Find the sum of squares of the greatest value and the smallest value of K in the number so that the number 45082K is divisible by 3.
How many composite numbers are there from 53 to 97 ?