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Question

Which one of the following bioreactor configurations is the basis for a trickling biological filter?

The correct answer is

 Packed bed

Trickling Filter: Packed Bed Bioreactor Basis

A trickling biological filter is a type of wastewater treatment system where microbial growth occurs on a fixed medium. The question asks which bioreactor configuration serves as its basis.

Understanding Bioreactor Configurations

Let's examine the options in relation to a trickling filter:

  • Stirred Tank: This configuration uses mechanical agitation to mix contents. It is not suitable for the fixed-film process of a trickling filter.
  • Packed Bed: This consists of a static bed of packing material (e.g., rocks, plastic) providing a large surface area for microbial colonization (biofilm). Wastewater trickles over this surface. This directly matches the structure of a trickling filter.
  • Air Lift: This configuration uses injected air for both mixing and aeration. While aeration is important, it doesn't define the fundamental structure of a trickling filter.
  • Fluidized Bed: Here, solid particles are suspended by upward fluid flow. This is different from the stationary media in a trickling filter.

Conclusion on Configuration

The design and operation of a trickling biological filter are fundamentally based on the Packed bed bioreactor configuration, due to the use of a static medium that supports biofilm growth.

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Important Questions from Heterocyclic Chemistry

  1. The major product formed in the following reaction sequences is

  2. The reaction(s) that yield(s) 2-methylquinoline as the major product is (are)
  3. The major products M and N formed in the following reactions are

  4. The structures of the major products W and X in the following synthetic scheme are 

  5. An enzyme converts substrate A to product B. At a given liquid feed stream of flow rate $25 \ L.min^{-1}$ and feed substrate concentration of $2 \ mol.L^{-1}$, the volume of continuous stirred tank reactor needed for 95% conversion will be ____________________ L. 

    Given the rate equation: $-r_A = \frac{0.1C_A}{1+0.5C_A}$ 

    where $-r_A$ is the rate of reaction in $mol.L^{-1}.min^{-1}$ and $C_A$ is the substrate concentration in $mol.L^{-1}$ 

    Assumptions: Enzyme concentration is contant and does not undergo any deactivation during the reaction.

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