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Question

Which of these numbers is divisible by 6?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is 45678

Understanding Divisibility by 6

To determine if a number is divisible by 6, we need to check if it meets two conditions:

  • The number must be divisible by 2.
  • The number must be divisible by 3.

Let's break down these rules:

  1. Divisibility by 2: A number is divisible by 2 if its last digit is an even number (0, 2, 4, 6, or 8). In other words, the number must be even.
  2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3.

A number is divisible by 6 only if both of these conditions are met.

Analyzing the Options for Divisibility by 6

Let's examine each of the given numbers to see if they are divisible by both 2 and 3.

Option 1: 34672

  • Divisibility by 2: The last digit is 2, which is an even number. So, 34672 is divisible by 2.
  • Divisibility by 3: Let's find the sum of the digits: \(3 + 4 + 6 + 7 + 2 = 22\). Is 22 divisible by 3? No, \(22 \div 3\) gives a remainder.

Since 34672 is divisible by 2 but not by 3, it is not divisible by 6.

Option 2: 45678

  • Divisibility by 2: The last digit is 8, which is an even number. So, 45678 is divisible by 2.
  • Divisibility by 3: Let's find the sum of the digits: \(4 + 5 + 6 + 7 + 8 = 30\). Is 30 divisible by 3? Yes, \(30 \div 3 = 10\).

Since 45678 is divisible by both 2 and 3, it is divisible by 6.

Option 3: 23456

  • Divisibility by 2: The last digit is 6, which is an even number. So, 23456 is divisible by 2.
  • Divisibility by 3: Let's find the sum of the digits: \(2 + 3 + 4 + 5 + 6 = 20\). Is 20 divisible by 3? No, \(20 \div 3\) gives a remainder.

Since 23456 is divisible by 2 but not by 3, it is not divisible by 6.

Option 4: 56792

  • Divisibility by 2: The last digit is 2, which is an even number. So, 56792 is divisible by 2.
  • Divisibility by 3: Let's find the sum of the digits: \(5 + 6 + 7 + 9 + 2 = 29\). Is 29 divisible by 3? No, \(29 \div 3\) gives a remainder.

Since 56792 is divisible by 2 but not by 3, it is not divisible by 6.

Summary of Divisibility Checks

Number Divisible by 2? (Ends in 0, 2, 4, 6, 8) Sum of Digits Sum Divisible by 3? Divisible by 6? (Both conditions met)
34672 Yes (ends in 2) 22 No No
45678 Yes (ends in 8) 30 Yes Yes
23456 Yes (ends in 6) 20 No No
56792 Yes (ends in 2) 29 No No

Based on our analysis, only the number 45678 is divisible by both 2 and 3, making it divisible by 6.

Revision Table: Divisibility Rules

Divisible by Rule Example
2 Last digit is 0, 2, 4, 6, or 8. 48 (ends in 8)
3 Sum of digits is divisible by 3. 123 (1+2+3=6, 6 is div by 3)
6 Divisible by both 2 and 3. 42 (div by 2 as it's even, div by 3 as 4+2=6)

Additional Information on Divisibility Rules

Divisibility rules are helpful shortcuts for determining if a number is divisible by another number without performing the actual division. They are based on the properties of numbers and place value.

  • Understanding prime factorization helps in creating divisibility rules for composite numbers like 6. Since \(6 = 2 \times 3\), a number is divisible by 6 if and only if it is divisible by its prime factors, 2 and 3.
  • These rules are useful in simplifying fractions, finding factors, and solving various arithmetic problems.
  • Other common divisibility rules exist for numbers like 4, 5, 9, 10, and 11. For example, a number is divisible by 4 if its last two digits form a number divisible by 4. A number is divisible by 5 if it ends in 0 or 5. A number is divisible by 9 if the sum of its digits is divisible by 9.
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Important Questions from Divisibility and Remainder

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