Which of the following numbers is divisible by 12?
83412
To determine if a number is divisible by 12, we need to check if it meets two conditions simultaneously. A number is divisible by 12 if and only if it is divisible by both 3 and 4.
Let's quickly review the divisibility rules for 3 and 4:
For a number to be divisible by 12, it must satisfy both of these rules.
We will now test each given number against the divisibility rules for 3 and 4.
| Number | Sum of Digits | Divisible by 3? (Sum ÷ 3) | Last Two Digits | Divisible by 4? (Last two digits ÷ 4) | Divisible by 12? (By 3 AND 4) |
|---|---|---|---|---|---|
| 93412 | 9 + 3 + 4 + 1 + 2 = 19 | No (19 is not divisible by 3) | 12 | Yes (12 ÷ 4 = 3) | No (Not divisible by both 3 and 4) |
| 73412 | 7 + 3 + 4 + 1 + 2 = 17 | No (17 is not divisible by 3) | 12 | Yes (12 ÷ 4 = 3) | No (Not divisible by both 3 and 4) |
| 83412 | 8 + 3 + 4 + 1 + 2 = 18 | Yes (18 ÷ 3 = 6) | 12 | Yes (12 ÷ 4 = 3) | Yes (Divisible by both 3 and 4) |
| 63412 | 6 + 3 + 4 + 1 + 2 = 16 | No (16 is not divisible by 3) | 12 | Yes (12 ÷ 4 = 3) | No (Not divisible by both 3 and 4) |
Based on our analysis, the number 83412 is divisible by 3 because the sum of its digits (18) is divisible by 3. It is also divisible by 4 because the number formed by its last two digits (12) is divisible by 4.
Since 83412 satisfies both the divisibility rule for 3 and the divisibility rule for 4, it is divisible by 12.
| Divisible By | Rule |
|---|---|
| 2 | The number is even (ends in 0, 2, 4, 6, or 8). |
| 3 | The sum of the digits is divisible by 3. |
| 4 | The number formed by the last two digits is divisible by 4. |
| 5 | The number ends in 0 or 5. |
| 6 | The number is divisible by both 2 and 3. |
| 9 | The sum of the digits is divisible by 9. |
| 10 | The number ends in 0. |
| 12 | The number is divisible by both 3 and 4. |
The rule that a number is divisible by 12 if it's divisible by both 3 and 4 works because 3 and 4 are coprime numbers. Coprime numbers (or relatively prime numbers) are numbers that have no common positive divisors other than 1. Since the greatest common divisor (GCD) of 3 and 4 is 1, their product (3 × 4 = 12) inherits the divisibility properties. If a number \(N\) can be written as \(N = 3k\) (divisible by 3) and \(N = 4m\) (divisible by 4) for some integers \(k\) and \(m\), then \(N\) must contain factors of both 3 and 4. Because 3 and 4 share no common factors other than 1, the number \(N\) must essentially be a multiple of their product, 12. So, \(N\) must be expressible as \(N = 12j\) for some integer \(j\), proving its divisibility by 12.
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select the correct answer using the code given below: