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Question

Which of the given letter-clusters will replace the question mark (?) in the following series?

FWJT, IZMW, LCPZ, ?, RIVF

The correct answer is

OFSC

Finding the Missing Letter Cluster in the Series

The question asks us to identify the letter cluster that completes the given series: FWJT, IZMW, LCPZ, ?, RIVF. To solve this, we need to find the pattern or rule that transforms one letter cluster into the next.

We will analyze the progression of letters at each corresponding position within the clusters.

Analyzing the First Letter of Each Cluster

  • The first letters are F, I, L, ?, R.
  • Let's look at their positions in the English alphabet:
Letter Alphabetical Position
F 6
I 9
L 12
R 18

  • From F to I: $9 - 6 = 3$. The position increased by 3.
  • From I to L: $12 - 9 = 3$. The position increased by 3.
  • The pattern for the first letter seems to be adding 3 to the alphabetical position.
  • Applying this pattern to L (position 12): $12 + 3 = 15$. The letter at position 15 is O.
  • Let's check if this pattern holds for the next step from O to R: O is at position 15, R is at position 18. $18 - 15 = 3$. Yes, it holds.
  • So, the first letter of the missing cluster is O.

Analyzing the Second Letter of Each Cluster

  • The second letters are W, Z, C, ?, I.
  • Let's look at their positions in the English alphabet:
Letter Alphabetical Position
W 23
Z 26
C 3
I 9

  • From W to Z: $26 - 23 = 3$. The position increased by 3.
  • From Z to C: This involves wrapping around the alphabet. Z is the 26th letter. Moving 3 steps from Z goes Z $\rightarrow$ A $\rightarrow$ B $\rightarrow$ C. So, $26 \xrightarrow{+1} \text{A} \xrightarrow{+1} \text{B} \xrightarrow{+1} \text{C}$. This is also a +3 pattern (26 + 3 = 29, and 29 is equivalent to position 3 when wrapping around 26 letters, $29 - 26 = 3$).
  • The pattern for the second letter seems to be adding 3 to the alphabetical position, with wrap-around from Z to A.
  • Applying this pattern to C (position 3): $3 + 3 = 6$. The letter at position 6 is F.
  • Let's check if this pattern holds for the next step from F to I: F is at position 6, I is at position 9. $9 - 6 = 3$. Yes, it holds.
  • So, the second letter of the missing cluster is F.

Analyzing the Third Letter of Each Cluster

  • The third letters are J, M, P, ?, V.
  • Let's look at their positions in the English alphabet:
Letter Alphabetical Position
J 10
M 13
P 16
V 22

  • From J to M: $13 - 10 = 3$. The position increased by 3.
  • From M to P: $16 - 13 = 3$. The position increased by 3.
  • The pattern for the third letter seems to be adding 3 to the alphabetical position.
  • Applying this pattern to P (position 16): $16 + 3 = 19$. The letter at position 19 is S.
  • Let's check if this pattern holds for the next step from S to V: S is at position 19, V is at position 22. $22 - 19 = 3$. Yes, it holds.
  • So, the third letter of the missing cluster is S.

Analyzing the Fourth Letter of Each Cluster

  • The fourth letters are T, W, Z, ?, F.
  • Let's look at their positions in the English alphabet:
Letter Alphabetical Position
T 20
W 23
Z 26
F 6

  • From T to W: $23 - 20 = 3$. The position increased by 3.
  • From W to Z: $26 - 23 = 3$. The position increased by 3.
  • The pattern for the fourth letter seems to be adding 3 to the alphabetical position, with wrap-around from Z to A.
  • Applying this pattern to Z (position 26): $26 + 3 = 29$. Wrapping around, position 29 is the same as position $29 - 26 = 3$. The letter at position 3 is C.
  • Let's check if this pattern holds for the next step from C to F: C is at position 3, F is at position 6. $6 - 3 = 3$. Yes, it holds.
  • So, the fourth letter of the missing cluster is C.

Combining the Letters

By combining the letters found for each position, we get the missing letter cluster:

  • First letter: O
  • Second letter: F
  • Third letter: S
  • Fourth letter: C

The missing letter cluster is OFSC.

Conclusion

The pattern for each corresponding letter position in the series is to advance by 3 positions in the alphabet, wrapping around from Z to A when necessary. Applying this logic, the missing letter cluster that replaces the question mark (?) is OFSC.

Revision Table: Letter Series Analysis

Cluster 1st Letter (+3) 2nd Letter (+3) 3rd Letter (+3) 4th Letter (+3)
FWJT F (6) W (23) J (10) T (20)
IZMW I (9) Z (26) M (13) W (23)
LCPZ L (12) C (3) P (16) Z (26)
OFSC O (15) F (6) S (19) C (3)
RIVF R (18) I (9) V (22) F (6)

Additional Information: Solving Letter Series Questions

Letter series questions are common in reasoning and aptitude tests. They require identifying a pattern in a sequence of letters or letter clusters. Here are some common patterns and strategies:

  • Positional Change: Letters advance or regress by a fixed number of positions in the alphabet.
  • Alternating Patterns: The pattern might alternate between different rules for successive terms.
  • Skipping Letters: Letters might be skipped in a sequence (e.g., ACFJ where the gap increases: +2, +3, +4).
  • Reverse Alphabetical Order: Letters might follow a pattern in reverse alphabetical order.
  • Combination of Patterns: Different positions within a cluster might follow different rules.
  • Alphabetical Position Mapping: Converting letters to their numerical position (A=1, B=2, ..., Z=26) often helps reveal numerical patterns.

Practice with various types of letter series questions is key to quickly identifying the underlying logic.

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Important Questions from Alphabet Series

  1. Select the letter-cluster from among the given options that can replace the question mark (?) in the following series.

    KMTC, EVOM, OQXG, IZSQ, ?

  2. Select the set of letters that when sequentially placed in the blanks of the given letter series will complete the series.

    k_lmml_mk_mmk_lkkl_m
  3. Select the letter will replace the question mark (?) in the following series.

    C, B, B, C, Z, E, W, H, S, ?, N
  4. Which letter will replace the question mark (?) in the following letter series?

    E, J, N, Q, S, ?

  5. Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series.
    C _ B N _ _ V_ _ H C _ B _ H

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