The length, cross-sectional area and material of the wire
The correct answer is 2. The length, cross-sectional area, and material of the wire.
The resistance (R) of a wire is determined by its physical properties according to the formula:
\( R = \rho \frac{L}{A} \)
Where:
This formula clearly shows that resistance is directly proportional to the length of the wire (\(L\)) and inversely proportional to its cross-sectional area (\(A\)). A longer wire has more resistance, while a thicker wire (larger area) has less resistance. The resistivity (\(\rho\)) is a material property and different materials have different resistivities. For example, copper has a much lower resistivity than nichrome, meaning copper wires have lower resistance for the same dimensions.
Therefore, all three factors – length, cross-sectional area, and material – influence the resistance of a wire.
If the length of a resistor is doubled, what happens to its resistance, assuming all other factors remain constant?
A cylindrical wire of length L and radius r has resistance R. The resistance of another wire of the same material but of twice its length and one-fourth its radius is:
Which of the following metals has the lowest electrical resistivity?
When electric current is passed through a wire, the amount of heat produced in a wire depends upon _______.
I. Length
II. Thickness
A uniform wire of resistance 9Ω is bent in the form of an equilateral triangle. Find the effective resistance across a side of the triangle.
The value of carbon resistance is 54 × 103 Ω. The percentage tolerance is 5%. What is the colour code sequence of carbon resistance?
Which of the following relations are wrong?
I. The specific conductance is given by the relation \(k = \frac{1}{R}\left( {l/A} \right)\)
II. The equivalent conducting is given by the relation \(\lambda = \frac{{100\;K}}{C}\)
III. The specific resistance is given by the relation \(\rho = \frac{{Rl}}{A}\)