A. The magnitude of resonance energy should be low and the hybrid will be more stable
B. The number of unpaired electrons should be same in all the canonical forms
C. Canonical forms where similar charges develop on vicinal atoms are highly significant forms
D. The positions of the nuclei of each canonical form and the hybrid must remain same
E. Only a pair of electrons should be shifted in writing the canonical forms
Choose the correct answer from the options given below :
Resonance structures, also known as canonical forms, are multiple Lewis structures that collectively represent the electron delocalization within a molecule. Several conditions must be met for valid resonance structures:
The total number of electrons, including unpaired ones, must remain constant across all resonance structures. Resonance involves the movement of electron pairs (lone pairs or pi electrons), not the creation or destruction of electrons.
The arrangement of atomic nuclei must be identical in all resonance structures and the resonance hybrid. Resonance only accounts for the delocalization of electrons, not the movement or rearrangement of atoms.
Only pi electrons (in double/triple bonds) and non-bonding valence electrons (lone pairs) can be delocalized. Sigma bonds remain intact. This movement typically involves pairs of electrons.
A *larger* magnitude of resonance energy indicates *greater* stability of the hybrid, not lower. Resonance energy is the difference between the actual hybrid's energy and that of the most stable hypothetical contributing structure. A significant difference implies stabilization.
While resonance can involve charge separation, developing similar charges (e.g., two positive charges or two negative charges) on adjacent (vicinal) atoms typically results in less stable canonical forms. Highly significant forms usually minimize such unfavorable charge arrangements.
Based on the analysis, the essential conditions for writing valid canonical structures are that the number of unpaired electrons must be the same (B), the positions of the nuclei must remain unchanged (D), and only pairs of electrons should be shifted (E). Therefore, options B, D, and E must be met.
Arrange the Hydrogen of the following compounds from most acidic to least acidic :
Choose the correct answer from the options given below :
| List - I (Number of d-electrons) | List - II (CFSE) |
|---|---|
| A. $\text{d}^{6}$ | I. $-0.4$ |
| B. $\text{d}^{4}$ | II. $-1.2$ |
| C. $\text{d}^{7}$ | III. $-0.8$ |
| D. $\text{d}^{8}$ | IV. $-0.6$ |
| List - I | List - II |
|---|---|
| A. Root mean square speed | I. $(8 \text{ kT}/\pi\mu)^{1/2}$ |
| B. Mean speed | II. $(8 \text{ RT}/\pi\text{M})^{1/2}$ |
| C. Most probable speed | III. $(3 \text{ RT}/\text{M})^{1/2}$ |
| D. Mean relative speed | IV. $(2 \text{ RT}/\text{M})^{1/2}$ |
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |