The question asks for the term that describes the average depth at which impurity atoms come to rest after losing energy through collisions during ion implantation into a crystal lattice.
Ion implantation is a process used to introduce impurity atoms (dopants) into a material, typically a semiconductor crystal. Energetic ions of the impurity are directed towards the crystal surface.
As the impurity ions penetrate the crystal lattice, they collide with the atoms of the crystal. During these collisions, the ions transfer their kinetic energy to the lattice atoms, gradually slowing down.
The depth at which these impurity atoms stop varies due to the probabilistic nature of atomic collisions. However, there is an average depth characteristic of the process under specific conditions.
This average depth, measured along the direction of incidence, is referred to as the Projected Range.
Therefore, the average penetration depth where impurity atoms come to rest is known as the Projected Range.
Arrange the Hydrogen of the following compounds from most acidic to least acidic :
Choose the correct answer from the options given below :
| List - I (Number of d-electrons) | List - II (CFSE) |
|---|---|
| A. $\text{d}^{6}$ | I. $-0.4$ |
| B. $\text{d}^{4}$ | II. $-1.2$ |
| C. $\text{d}^{7}$ | III. $-0.8$ |
| D. $\text{d}^{8}$ | IV. $-0.6$ |
| List - I | List - II |
|---|---|
| A. Root mean square speed | I. $(8 \text{ kT}/\pi\mu)^{1/2}$ |
| B. Mean speed | II. $(8 \text{ RT}/\pi\text{M})^{1/2}$ |
| C. Most probable speed | III. $(3 \text{ RT}/\text{M})^{1/2}$ |
| D. Mean relative speed | IV. $(2 \text{ RT}/\text{M})^{1/2}$ |
| List-I | List-II |
| Electronic Configuration | First Ionisation energy (kJ mol$^{-1}$) |
| (A). ns$^2$ | (I). 2100 |
| (B). ns$^2$np$^1$ | (II). 1400 |
| (C). ns$^2$np$^3$ | (III). 800 |
| (D). ns$^2$np$^6$ | (IV). 900 |
| List-I | List-II |
| Spectroscopy | Property |
| (A). Raman | (I). Polarizability |
| (B). FTIR | (II). Dipole Moment |
| (C). UV-Visible | (III). Absorbance |
| (D). NMR | (IV). Spin |