Which among the following molecular formulae of organic compounds does NOT represent a ring structure?
C6H14
A quick way to tell whether a hydrocarbon can be an open-chain (acyclic) compound is the general formula for saturated open-chain alkanes: \(C_nH_{2n+2}\). Any formula that matches this exactly can be drawn as a straight or branched chain with no ring. Formulae with fewer hydrogens than \(2n+2\) must contain either a double/triple bond or a ring (each ring or pi bond reduces the hydrogen count by 2).
For n = 6, the alkane formula is \(C_6H_{14}\), which corresponds to n-hexane and its branched isomers, all open-chain molecules with no ring.
The other three options have fewer hydrogens than \(C_6H_{14}\). \(C_6H_{10}\) fits cyclohexene (one ring plus one double bond), \(C_6H_6\) is benzene (a six-membered aromatic ring), and \(C_6H_8\) fits cyclohexadiene (a ring with two double bonds). Each of these must be drawn with a ring.
Hence, the molecular formula that does NOT represent a ring structure is \(C_6H_{14}\).
Similar Questions
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Which property is most affected if the length of the carbon chain in an alkane increases?
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Assertion (A): Unsaturated hydrocarbons give a yellow flame with black smoke.
Reason (R): They burn completely when oxygen is insufficient.
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(1) All members have the same general formula.
(2) Each successive member differs by a \(-CH_2-\) group.
(3) Physical properties remain identical for all members.
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A compound has the molecular formula C4H10. Which statement best describes its structure?
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Important Questions from Hydrocarbons
- Which structural feature contributes to the high reactivity of unsaturated organic compounds?
- Unsaturated hydrocarbons usually produce:
- Which property of carbon allows it to form a large number of compounds by bonding with itself and other elements?
- Which type of bond is present between carbon atoms in saturated hydrocarbons?
- Power Alcohol is a mixture of ______ and ethyl alcohol.
