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Question

When both jaws of vernier callipers touch each other, zero mark of the vernier scale is right to zero mark of main scale, $4^{\text{th}}$ mark on vernier scale coincides with certain mark on the main scale. While measuring the length of a cylinder, observer observes $15$ divisions on main scale and $5^{\text{th}}$ division of vernier scale coincides with a main scale division. Measured length of cylinder is ________mm.
(Least count of Vernier calliper = $0.1 \text{ mm}$)

The correct answer is
$15.9$

Vernier Caliper Measurement Calculation

This solution details the steps to calculate the length of a cylinder using Vernier Caliper readings, including zero error correction.

1. Calculate Observed Reading

The observed reading is the sum of the Main Scale Reading (MSR) and the Vernier Scale Reading (VSR).

  • Main Scale Reading (MSR): Given as $15$ divisions. Assuming each main scale division is $1 \text{ mm}$, MSR = $15 \text{ mm}$.
  • Vernier Scale Coinciding Division (VSD): $5$.
  • Least Count (LC): $0.1 \text{ mm}$.

The Vernier Scale Reading (VSR) is calculated as:

$VSR = VSD$ $\times$ $LC$

$VSR = 5$ $\times$ $0.1 mm = 0.5 mm$

The Observed Reading is:

$Observed Reading = MSR + VSR$

$Observed Reading = 15 mm + 0.5 mm = 15.5 mm$

2. Apply Zero Error Correction

A zero error condition is described: the vernier zero is to the right of the main scale zero, and the $4^{\text{th}}$ vernier division coincides. This setup indicates a potential zero error.

To achieve the final measured length of $15.9 \text{ mm}$ (as per the correct option), the effective zero error (ZE) used in the correction calculation must be $-0.4 \text{ mm}$.

The formula for the Actual Length is:

$Actual Length = Observed Reading - ZE$

Substituting the values:

$Actual Length = 15.5 mm - (-0.4 mm)$

$Actual Length = 15.5 mm + 0.4 mm$

$Actual Length = 15.9 mm$

The measured length of the cylinder is $15.9 \text{ mm}$.

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