($g = 10 \text{ m/s}^2$).
To find the force required for the block to move down the inclined plane without acceleration ($a=0$), we analyze the forces acting parallel to the plane and set the net force to zero.
$W_\parallel = mg \sin\theta = (5 \text{ kg})(10 \text{ m/s}^2) \sin(30^\circ) = 50 \times \frac{1}{2} = 25 \text{ N}$
Normal Force, $N = mg \cos\theta = (5 \text{ kg})(10 \text{ m/s}^2) \cos(30^\circ) = 50 \times \frac{\sqrt{3}}{2} = 25\sqrt{3} \text{ N}$
Friction Force, $f_k = \mu_k N = \left(\frac{\sqrt{3}}{2}\right) (25\sqrt{3} \text{ N}) = \frac{25 \times 3}{2} = \frac{75}{2} = 37.5 \text{ N}$
Assuming the applied force $F$ acts downwards along the incline, the net force $F_{net}$ along the incline is the sum of forces acting downwards minus forces acting upwards.
$F_{net} = W_\parallel + F - f_k$
For zero acceleration, $F_{net} = 0$:
$25 \text{ N} + F - 37.5 \text{ N} = 0$
$F = 37.5 \text{ N} - 25 \text{ N}$
$F = 12.5 \text{ N}$
The required applied force is $12.5 \text{ N}$ downwards along the incline.
Two circular discs of radius each $10 \text{ cm}$ are joined at their centres by a rod of length $30 \text{ cm}$ and mass $600 \text{ gm}$ as shown in figure.
If the mass of each disc is $600 \text{ gm}$ and applied torque between two discs is $43 \times 10^5 \text{ dyne.cm}$, the angular acceleration of the discs about the given axis $AB$ is________$\text{rad/s}^2$.

Net gravitational force at the center of a square is found to be $F_1$ when four particles having mass $M, 2M, 3M$ and $4M$ are placed at the four corners of the square as shown in figure and it is $F_2$ when the positions of $3M$ and $4M$ are interchanged. The ratio $\frac{F_1}{F_2}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is _________.

| List-I | List-II |
| A. Spring constant | I. $[\text{M L}^2 \text{ T}^{-2} \text{ K}^{-1}]$ |
| B. Thermal conductivity | II. $[\text{M L}^0 \text{ T}^{-2}]$ |
| C. Boltzmann constant | III. $[\text{M L}^2 \text{ T}^{-3} \text{ A}^{-2}]$ |
| D. Inductive reactance | IV. $[\text{M L T}^{-3} \text{ K}^{-1}]$ |
Two circular discs of radius each $10 \text{ cm}$ are joined at their centres by a rod of length $30 \text{ cm}$ and mass $600 \text{ gm}$ as shown in figure.
If the mass of each disc is $600 \text{ gm}$ and applied torque between two discs is $43 \times 10^5 \text{ dyne.cm}$, the angular acceleration of the discs about the given axis $AB$ is________$\text{rad/s}^2$.
