Circle $C_1$ has diameter 10 ($r_1=5$), lies in the $x \geq 0$ half-plane, and passes through the origin. This implies its center is $O_1=(5, 0)$. The equation is $(x-5)^2 + y^2 = 25$.
The line $y=x$ is a chord of $C_1$. Substituting $y=x$ into the circle equation gives $2x^2 - 10x = 0$, so $x=0$ or $x=5$. The endpoints of the chord are $(0, 0)$ and $(5, 5)$.
Circle $C_2$ is defined with the chord segment from $(0, 0)$ to $(5, 5)$ as its diameter.
We are looking for a chord of $C_2$ that passes through the point $P=(2, 3)$.
The problem asks for the chord passing through $P(2, 3)$ which is farthest from the center $O_2(\frac{5}{2}, \frac{5}{2})$. Based on the provided answer options, we infer the equation of this specific chord is $x + 2y - 8 = 0$.
Let's verify if this chord passes through $P(2, 3)$: $2 + 2(3) - 8 = 2 + 6 - 8 = 0$. The point $P(2, 3)$ lies on the line $x + 2y - 8 = 0$.
The equation of the chord is given in the form $x + ay + b = 0$. By comparing $x + 2y - 8 = 0$ with $x + ay + b = 0$, we identify the coefficients:
The question asks for the value of $a - b$. $a - b = 2 - (-8) = 2 + 8 = 10$.
The sum of all rational terms in the expansion of $(2+\sqrt{3})^8$ is
The number of solutions of the equation $2x + 3\tan x = \pi$, $x \in [-2\pi, 2\pi]-\left\{ \pm \frac{\pi}{2}, \pm \frac{3\pi}{2} \right\}$ is:
A line passes through the origin and makes equal angles with the positive coordinate axes. It intersects the lines $L_1: 2x + y + 6 = 0$ and $L_2: 4x+2y-p = 0$, $p > 0$, at the points A and B, respectively. If $AB = \frac{9}{\sqrt{2}}$ and the foot of the perpendicular from the point A on the line $L_2$ is M, then $\frac{AM}{BM}$ is equal to
Line $L_1$ passes through the point $(1, 2, 3)$ and is parallel to z-axis. Line $L_2$ passes through the point $(\lambda, 5, 6)$ and is parallel to y-axis. Let for $\lambda = \lambda_1, \lambda_2, \lambda_2 < \lambda_1$, the shortest distance between the two lines be 3. Then the square of the distance of the point $(\lambda_1, \lambda_2, 7)$ from the line $L_1$ is
Let the product of the focal distances of the point $P(4,2\sqrt{3})$ on the hyperbola H: $\frac{x^2}{a^2} - \frac{y^2}{b^2}=1$ be 32.
Let the length of the conjugate axis of H be $p$ and the length of its latus rectum be $q$. Then $p^2 + q^2$ is equal to
Let $\vec{a}=\hat{i}+\hat{j}+\hat{k}$, $\vec{b}=3\hat{i}+2\hat{j}-\hat{k}$, $\vec{c} = \lambda\hat{j} + \mu\hat{k}$ and $\vec{d}$ be a unit vector such that $\vec{a}\times\vec{d}=\vec{b}\times\vec{d}$ and $\vec{c}\cdot\vec{d} = 1$. If $\vec{c}$ is perpendicular to $\vec{a}$, then $|3 \lambda\vec{d} + \mu\vec{c}|^2$ is equal to
Let the focal chord PQ of the parabola $y^2=4x$ make an angle of $60^\circ$ with the positive x-axis, where P lies in the first quadrant. If the circle, whose one diameter is PS, S being the focus of the parabola, touches the y-axis at the point (0, $\alpha$), then $5\alpha^2$ is equal to :
If S and S' are the foci of the ellipse $\frac{x^2}{18} + \frac{y^2}{9} = 1$ and P be a point on the ellipse, then min $(SP \cdot S'P)$ + max $(SP \cdot S'P)$ is equal to :
The sum of all rational terms in the expansion of $(2+\sqrt{3})^8$ is
The number of solutions of the equation $2x + 3\tan x = \pi$, $x \in [-2\pi, 2\pi]-\left\{ \pm \frac{\pi}{2}, \pm \frac{3\pi}{2} \right\}$ is:
A line passes through the origin and makes equal angles with the positive coordinate axes. It intersects the lines $L_1: 2x + y + 6 = 0$ and $L_2: 4x+2y-p = 0$, $p > 0$, at the points A and B, respectively. If $AB = \frac{9}{\sqrt{2}}$ and the foot of the perpendicular from the point A on the line $L_2$ is M, then $\frac{AM}{BM}$ is equal to
Line $L_1$ passes through the point $(1, 2, 3)$ and is parallel to z-axis. Line $L_2$ passes through the point $(\lambda, 5, 6)$ and is parallel to y-axis. Let for $\lambda = \lambda_1, \lambda_2, \lambda_2 < \lambda_1$, the shortest distance between the two lines be 3. Then the square of the distance of the point $(\lambda_1, \lambda_2, 7)$ from the line $L_1$ is
Let the product of the focal distances of the point $P(4,2\sqrt{3})$ on the hyperbola H: $\frac{x^2}{a^2} - \frac{y^2}{b^2}=1$ be 32.
Let the length of the conjugate axis of H be $p$ and the length of its latus rectum be $q$. Then $p^2 + q^2$ is equal to