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Question

What will come in the place of the question mark ‘?’ in the following question?

420 ÷ 28 × 288 ÷ 32 = ?

This question was previously asked in
ESIC UDC Mains MBT (30 Apr 2022)
The correct answer is

135

Question Mark Value Calculation

The problem asks us to determine the numerical value that should replace the question mark ('?') in the given mathematical expression:

$$ 420 \div 28 \times 288 \div 32 = ? $$

To solve this accurately, we must adhere to the standard order of operations, commonly known as BODMAS or PEMDAS. This rule dictates the sequence in which mathematical operations should be performed: Brackets, Orders (powers and roots), Division and Multiplication (from left to right), and Addition and Subtraction (from left to right).

Step-by-Step Calculation Process

In this expression, we only have division and multiplication operations. According to the order of operations, we perform these from left to right.

  1. First Step: Leftmost Division

    We start by performing the division that appears first from the left:

    $$ 420 \div 28 $$

    Calculating this division:

    $$ \frac{420}{28} = 15 $$

    After this step, the expression simplifies to:

    $$ 15 \times 288 \div 32 $$

  2. Second Step: Multiplication

    Next, we proceed with the multiplication operation, moving from left to right:

    $$ 15 \times 288 $$

    Performing the multiplication:

    $$ 15 \times 288 = 4320 $$

    The expression is now reduced to a single division:

    $$ 4320 \div 32 $$

  3. Third Step: Final Division

    Finally, we perform the last operation, which is division:

    $$ 4320 \div 32 $$

    Calculating the final result:

    $$ \frac{4320}{32} = 135 $$

Result Summary

By following the order of operations systematically, we find that the value which should come in place of the question mark is 135.

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Important Questions from Simplification

  1. Simplify

    6 × {28 ÷ 84 × {36 × 49 ÷ (6 × 7)}}.

  2. Simplify.

  3. A bag contains ₹5, 2 and 1 coins in the ratio of 3 : 4 : 5. The total value of all the coins is ₹2,100. How many coins of ₹5 are there in the bag?
  4. \(\frac{6}{2}\times\frac{10}{2}\div\frac{6}{2}\times6^2+5\times4=?\)
  5. Find the value of 2.\(\overline {36} \) + 3.\(\overline {21} \) - 1.\(\overline {05} \)
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