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Question

What will come in place of question mark (?) in the following equation?

(√25 × 12) ÷ 15 + √256 = ?

This question was previously asked in
ESIC UDC Mains MBT (30 Apr 2022)
The correct answer is

20

Equation Calculation: Step-by-Step Solution

This solution details how to find the value represented by the question mark (?) in the given mathematical equation. We will solve the equation step-by-step, applying the order of operations (PEMDAS/BODMAS) and simplifying each part.

Understanding the Equation

The equation we need to solve is:

$$ \left ( \sqrt{25} \times 12 \right ) \div 15 + \sqrt{256} = ? $$

To find the value of '?', we must first calculate the square roots, then perform the multiplication, followed by the division, and finally the addition.

Step 1: Calculate Square Roots

First, we find the square root of 25 and 256:

  • The square root of 25, denoted as $ \sqrt{25} $, is 5. This is because $ 5 \times 5 = 25 $.
  • The square root of 256, denoted as $ \sqrt{256} $, is 16. This is because $ 16 \times 16 = 256 $.

Substituting these values back into the equation:

$$ (5 \times 12) \div 15 + 16 = ? $$

Step 2: Perform Multiplication

Next, we perform the multiplication inside the parentheses:

  • $ 5 \times 12 = 60 $

The equation now becomes:

$$ 60 \div 15 + 16 = ? $$

Step 3: Perform Division

Now, we carry out the division operation:

  • $ 60 \div 15 = 4 $

The equation simplifies to:

$$ 4 + 16 = ? $$

Step 4: Perform Addition

Finally, we perform the addition to find the final value:

  • $ 4 + 16 = 20 $

Final Result

Therefore, the value that comes in place of the question mark (?) is 20.

$$ ? = 20 $$

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Important Questions from Simplification

  1. Simplify

    6 × {28 ÷ 84 × {36 × 49 ÷ (6 × 7)}}.

  2. Simplify.

  3. A bag contains ₹5, 2 and 1 coins in the ratio of 3 : 4 : 5. The total value of all the coins is ₹2,100. How many coins of ₹5 are there in the bag?
  4. \(\frac{6}{2}\times\frac{10}{2}\div\frac{6}{2}\times6^2+5\times4=?\)
  5. Find the value of 2.\(\overline {36} \) + 3.\(\overline {21} \) - 1.\(\overline {05} \)
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