The question asks to find the principal sum (P) given the simple interest (SI), time period (T), and annual interest rate (R).
Given:
The formula for Simple Interest is:
\(SI = \frac{P \times R \times T}{100}\)
To find the principal sum (P), we can rearrange the formula:
\(P = \frac{SI \times 100}{R \times T}\)
\(P = \frac{480 \times 100}{5 \times 2}\)
\(P = \frac{48000}{5 \times 2}\)
\(P = \frac{48000}{10}\)
\(P = 4800\)
Therefore, the sum that will earn an interest of ₹480 in 2 years at 5% simple interest per year is ₹4800.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.