The marks obtained by 10 students in a Statistics test are 24, 47, 18, 32, 19, 15, 21, 35, 50 and 41.
This problem requires calculating the variance of a specific subset of data – the largest five observations from a list of student marks in a Statistics test. Variance measures how spread out the data points are from their average value (mean).
The marks obtained by 10 students are:
24, 47, 18, 32, 19, 15, 21, 35, 50, 41
First, we need to sort the marks in ascending order to easily identify the largest values:
15, 18, 19, 21, 24, 32, 35, 41, 47, 50
The largest five observations are:
32, 35, 41, 47, 50
To find the variance, we first need the mean (\(\bar{x}\)) of these five numbers.
Mean (\(\bar{x}\)) = Sum of observations / Number of observations
\(\bar{x} = \frac{32 + 35 + 41 + 47 + 50}{5}\)
\(\bar{x} = \frac{205}{5}\)
\(\bar{x} = 41\)
Variance measures the average squared difference of each data point from the mean. Since we are considering these five observations as the complete set of interest for this calculation, we use the formula for population variance (\(\sigma^2\)):
Population Variance (\(\sigma^2\)) = \(\frac{\sum_{i=1}^{N}(x_i - \bar{x})^2}{N}\)
Where:
Let's calculate the squared difference for each observation:
Now, sum these squared differences:
Sum of squared differences = \(81 + 36 + 0 + 36 + 81 = 234\)
Finally, calculate the variance by dividing the sum of squared differences by the number of observations (\(N=5\)):
\(\sigma^2 = \frac{234}{5}\)
\(\sigma^2 = 46.8\)
Therefore, the variance of the largest five observations is 46.8.
What is the median height of the class?
What is the total number of students whose height is less than or equal to 165 cm?
The height which occurs most frequently in the class is
| LIST-I | LIST-II | |
| A. Sampling error | I. | Values that describe the characteristics of a population |
| B. Parameters | II. | The standard deviation of the sampling distribution |
| C. Sampling fraction | III. | Variation among sample statistics due to change |
| D. Standard error | IV. | Proportion of the population contained in a sample |
Given below are two statements one is labelled as Assertion (A) and the other is labelled as
Reason (R).
Assertion (A): Additive model considers the total of various components resulting in the given
values of the over all time series and it is stated as:
$Y=T+C+S+I$
Reason (R): Multiplicative model assumes that the various components interact in a
multiplicative manner to produce the given values of the over all time series and
can be stated as $Y=T \times C \times S \times I$
In the light of the above statements, choose the most appropriate answer from the options given
below:
Match List - I with List - II.
| List - I | List - II |
| A. Sample proportion P = x/n | I. $\frac{\sigma}{\sqrt{n}}$ |
| B. Sample variance $S_1^2 = \frac{1}{n-1} \sum_{i=1}^{n}(xi-x̄)^2$ | II. $\sigma^2 \sqrt{\frac{2}{n}}$ |
| C. Sample variance $S^2 = \frac{1}{n} \sum_{i=1}^{n}(xi-x̄)^2$ | III. $\sigma^2 \sqrt{\frac{2}{(n-1)}}$ |
| D. Sample mean $\bar{x} = \frac{1}{n} \sum_{i=1}^{n}xi$ | IV. $\sqrt{\frac{\pi(1-\pi)}{n}}$ |
Choose the correct answer from the options given below :