Calculate Square Root Values
First, find the square root of each number given in the expression.
- To find $\sqrt{9801}$: We look for a number whose square is 9801. We know $90^2 = 8100$ and $100^2 = 10000$. Since 9801 ends in 1, the root must end in 1 or 9. Trying 99, we get $99 \times 99 = 9801$. Thus, $\sqrt{9801} = 99$.
- To find $\sqrt{1681}$: We look for a number whose square is 1681. We know $40^2 = 1600$. Since 1681 ends in 1, the root must end in 1 or 9. Trying 41, we get $41 \times 41 = 1681$. Thus, $\sqrt{1681} = 41$.
Subtracting Square Roots
Now, subtract the second square root value from the first one.
The expression becomes:
$99 - 41$
Performing the subtraction:
$99 - 41 = 58$
The final value of the expression $\sqrt{9801} - \sqrt{1681}$ is 58.
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Important Questions from Simplification
Simplify the following expression.
\(\left(\frac{7}{16} \div \frac{1}{2}\:of\: \frac{1}{5}\right)\times \frac{4}{5}-\frac{1}{3}\times\frac{5}{8}\div \frac{1}{2}+\frac{3}{4}\)
The value of \(\left( {2\frac{6}{7}of4\frac{1}{5} \div \frac{2}{3}} \right) \times 5\frac{1}{9} \div \left( {\frac{3}{4} \times 2\frac{2}{3}of\frac{1}{2} \div \frac{1}{4}} \right)\) is:
The value of \(\left[ {\frac{4}{7}\rm \;of\;2\frac{4}{5} \times 1\frac{2}{3} - \left( {3\frac{1}{2} - 2\frac{1}{6}} \right)} \right] \div \left( {3\frac{1}{5} \div 4\frac{1}{2}\;\rm of\;\;5\frac{1}{3}} \right)\) is:
The value of \(\frac{{0.0203 \times 2.92}}{{0.7 \times 0.0365 \times 2.9}} \div \frac{{{{\left( {12.12} \right)}^2} - {{\left( {8.12} \right)}^2}}}{{{{\left( {0.25} \right)}^2} + \left( {0.25} \right)\left( {19.99} \right)}}\) is:
The value of 4 ÷ 12 of [3 ÷ 4 of {(4 - 2) × 6 ÷ 2}] - 2 × 6 ÷ 8 + 3 is:
