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Question

What is the simplified value of: $$\frac{0.01404}{24^2+6^2-144}$$

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
$3 \times 10^{-5}$

The question asks for the simplified value of the expression: $ \frac{0.01404}{24^2+6^2-144} $ We need to calculate the denominator first and then perform the division.

Denominator Calculation

First, calculate the squares in the denominator:

  • $24^2 = 576$
  • $6^2 = 36$

Now, substitute these values back into the denominator expression:

$ \text{Denominator} = 24^2 + 6^2 - 144 $ $ \text{Denominator} = 576 + 36 - 144 $

Perform the addition and subtraction:

$ \text{Denominator} = 612 - 144 $ $ \text{Denominator} = 468 $

Fraction Simplification

Now substitute the calculated denominator back into the original fraction:

$ \frac{0.01404}{468} $

To simplify this, we can perform the division. It's helpful to write the numerator in scientific notation:

$ 0.01404 = 1.404 \times 10^{-2} $

The expression becomes:

$ \frac{1.404 \times 10^{-2}}{468} $

Now, divide the numbers:

$ \frac{1.404}{468} = 0.003 $

So the expression simplifies to:

$ 0.003 \times 10^{-2} $

Convert $0.003$ to scientific notation:

$ 0.003 = 3 \times 10^{-3} $

Combine the terms:

$ (3 \times 10^{-3}) \times 10^{-2} $

Using the rule of exponents ($a^m \times a^n = a^{m+n}$):

$ 3 \times 10^{-3 + (-2)} $ $ 3 \times 10^{-5} $

The simplified value is $3 \times 10^{-5}$.

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