A car travels 13.5 km using 1.8 liters of fuel. How many kilometers does it travel per liter?
7.5 km
The distance travelled is 13.5 km using 1.8 litres of fuel, so the mileage is found by dividing distance by fuel used.
\(\text{Mileage} = \frac{13.5}{1.8}\).
Simplifying, \(\frac{13.5}{1.8} = 7.5\).
Hence, the answer is 7.5 km per litre.
What will come in place of ? to satisfy the equation :
$(\sqrt{5}-1)^2 = ?-2\sqrt{5}$
What will take the place of "?" in the given equation: \(\dfrac{?}{\sqrt{81}} = \dfrac{\sqrt{121}}{10+1}\)
Simplify the following expression.
\(\left(\frac{7}{16} \div \frac{1}{2}\:of\: \frac{1}{5}\right)\times \frac{4}{5}-\frac{1}{3}\times\frac{5}{8}\div \frac{1}{2}+\frac{3}{4}\)
The value of \(\left( {2\frac{6}{7}of4\frac{1}{5} \div \frac{2}{3}} \right) \times 5\frac{1}{9} \div \left( {\frac{3}{4} \times 2\frac{2}{3}of\frac{1}{2} \div \frac{1}{4}} \right)\) is:
The value of \(\left[ {\frac{4}{7}\rm \;of\;2\frac{4}{5} \times 1\frac{2}{3} - \left( {3\frac{1}{2} - 2\frac{1}{6}} \right)} \right] \div \left( {3\frac{1}{5} \div 4\frac{1}{2}\;\rm of\;\;5\frac{1}{3}} \right)\) is:
The value of \(\frac{{0.0203 \times 2.92}}{{0.7 \times 0.0365 \times 2.9}} \div \frac{{{{\left( {12.12} \right)}^2} - {{\left( {8.12} \right)}^2}}}{{{{\left( {0.25} \right)}^2} + \left( {0.25} \right)\left( {19.99} \right)}}\) is:
The value of 4 ÷ 12 of [3 ÷ 4 of {(4 - 2) × 6 ÷ 2}] - 2 × 6 ÷ 8 + 3 is: