What is the value of cot (90 + 75°)?
-2 - √3
Using \(\cot(90^\circ+\theta)=-\tan\theta\):
\[\cot(90^\circ+75^\circ)=-\tan 75^\circ\]
Compute \(\tan 75^\circ\): \(\tan(45^\circ+30^\circ)=\dfrac{1+1/\sqrt 3}{1-1/\sqrt 3}=\dfrac{\sqrt 3+1}{\sqrt 3-1}=2+\sqrt 3\).
Therefore \(\cot(165^\circ)=-(2+\sqrt 3)=\mathbf{-2-\sqrt 3}\).
θ = 135°; γ = 15°.
What is the value of 2 cos(θ) sin(γ)?
Solve the following.
\({\left( {\frac{{sin27^\circ }}{{cos63^\circ }} - \frac{{cos27^\circ }}{{sin63^\circ }}} \right)^2}\)
The value of \(\rm \frac{(cos\,9^\circ+sin \,81^\circ)(sec\,9^\circ+cosec\,81^\circ)}{cosec^2\,71^\circ+cos^2\,15^\circ-tan^2\,19^\circ+cos^2\,75^\circ} \) is:
Find the value of sin 4 30° + cos 4 30° - sin 25° cos 65° - sin 65° cos25°.
Find the value of \(cosec(60° + A) - sec(30° - A) +\frac{cosec49^{\circ}}{sec 41^{\circ}}\) .
If sin 6θ + cos 6 θ = \(\frac{1}{3}\) , 0° < θ < 90°, then what is the value of sinθ cosθ?
(secθ + tan θ )2 + \(\frac{1 + cosec θ}{1 - cosec θ'}\) 0° < θ < 90° is:
Find the value of \(\rm \frac{tan^230^\circ}{sec^230^\circ}+\frac{cosec^245^\circ}{cot^245^\circ}-\frac{sec^260^\circ}{cosec^260^\circ}\)
What is the value of sin(630 + A) + cosA?
If (A + B + C) = 90°, then what is the value of sin (A / 2) sin [(180 - B - C) / 2] + cos (A / 2) sin (B + C) / 2?
If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.
1 + tan 15° cot 75° is equal to:
The value of cot (-315°) is :
θ = 135°; γ = 15°.
What is the value of 2 cos(θ) sin(γ)?
If tan(90 – θ) = \(\frac{2}{\sqrt3}\), then the value of \(2\sqrt3\) tan θ + 1 is: