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Question

Solve the following.

\({\left( {\frac{{sin27^\circ }}{{cos63^\circ }} - \frac{{cos27^\circ }}{{sin63^\circ }}} \right)^2}\)

This question was previously asked in
SSC CGL 2019 (Tier 2) GS Finance & Economics Previous Year Paper (17-Nov-2020)
The correct answer is

0

Understanding the Trigonometric Expression

The problem asks us to evaluate the expression \({\left( {\frac{{sin27^\circ }}{{cos63^\circ }} - \frac{{cos27^\circ }}{{sin63^\circ }}} \right)^2}\). This expression involves trigonometric ratios of angles that seem different (27° and 63°), but they are related through the concept of complementary angles.

Applying Complementary Angle Identities

Two angles are called complementary if their sum is 90°. In this case, 27° + 63° = 90°, so 27° and 63° are complementary angles.

We can use the following complementary angle identities:

  • \(\sin(90^\circ - \theta) = \cos \theta\)
  • \(\cos(90^\circ - \theta) = \sin \theta\)

Using these identities, we can relate the trigonometric ratios of 63° to those of 27°:

  • \(\cos63^\circ = \cos(90^\circ - 27^\circ) = \sin27^\circ\)
  • \(\sin63^\circ = \sin(90^\circ - 27^\circ) = \cos27^\circ\)

Simplifying the Expression

Now, substitute these equivalent expressions back into the original equation:

\({\left( {\frac{{sin27^\circ }}{{cos63^\circ }} - \frac{{cos27^\circ }}{{sin63^\circ }}} \right)^2}\)

Substitute \(\cos63^\circ = \sin27^\circ\) and \(\sin63^\circ = \cos27^\circ\):

\({\left( {\frac{{sin27^\circ }}{{sin27^\circ }} - \frac{{cos27^\circ }}{{cos27^\circ }}} \right)^2}\)

Assuming \(\sin27^\circ \ne 0\) and \(\cos27^\circ \ne 0\) (which is true for 27°), the fractions simplify:

  • \(\frac{{sin27^\circ }}{{sin27^\circ }} = 1\)
  • \(\frac{{cos27^\circ }}{{cos27^\circ }} = 1\)

So the expression becomes:

\({\left( {1 - 1} \right)^2}\)

Perform the subtraction inside the parenthesis:

\({\left( 0 \right)^2}\)

Finally, calculate the square:

\({0^2} = 0\)

Step-by-Step Calculation

Let's break down the solution process:

  1. Identify the angles in the expression: 27° and 63°.
  2. Check if they are complementary: 27° + 63° = 90°. Yes, they are.
  3. Use complementary angle identities: \(\cos63^\circ = \sin27^\circ\) and \(\sin63^\circ = \cos27^\circ\).
  4. Substitute these into the expression: \({\left( {\frac{{sin27^\circ }}{{\sin27^\circ }} - \frac{{cos27^\circ }}{{\cos27^\circ }}} \right)^2}\).
  5. Simplify the fractions: \({\left( {1 - 1} \right)^2}\).
  6. Calculate the value: \({\left( 0 \right)^2} = 0\).

The final value of the given expression is 0.

Expression Part Transformation/Identity Result
\(\cos63^\circ\) \(\cos(90^\circ - 27^\circ)\) \(\sin27^\circ\)
\(\sin63^\circ\) \(\sin(90^\circ - 27^\circ)\) \(\cos27^\circ\)
\(\frac{{sin27^\circ }}{{cos63^\circ }}\) \(\frac{{sin27^\circ }}{{sin27^\circ }}\) 1
\(\frac{{cos27^\circ }}{{sin63^\circ }}\) \(\frac{{cos27^\circ }}{{cos27^\circ }}\) 1
Inside Parentheses \(1 - 1\) 0
Final Expression \({0^2}\) 0

Revision Table: Key Trigonometry Concepts

Concept Description Relevant Identity Example
Trigonometric Ratios Ratios of sides of a right-angled triangle (sin, cos, tan, etc.) \(\sin\theta = \frac{{Opposite}}{{Hypotenuse}}\)
Complementary Angles Two angles that add up to 90° 27° and 63° are complementary
Complementary Angle Identities Relates trig ratios of complementary angles \(\sin(90^\circ - \theta) = \cos \theta\), \(\cos(90^\circ - \theta) = \sin \theta\)

Additional Information: Complementary Angles in Practice

Understanding complementary angles is very useful in trigonometry. It allows us to simplify expressions involving angles like 10° and 80°, 45° and 45°, etc. For instance, if you need to find \(\tan 80^\circ\) but only know values for angles up to 45°, you can use the identity \(\tan(90^\circ - \theta) = \cot \theta\). So, \(\tan 80^\circ = \tan(90^\circ - 10^\circ) = \cot 10^\circ\).

The co-function identities (like \(\sin \leftrightarrow \cos\), \(\tan \leftrightarrow \cot\), \(\sec \leftrightarrow \csc\)) stem directly from the concept of complementary angles in a right-angled triangle. If one acute angle is \(\theta\), the other acute angle is \(90^\circ - \theta\).

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Similar Questions

  1. θ = 135°; γ = 15°.

    What is the value of 2 cos(θ) sin(γ)?

  2. What is the value of cot (90 + 75°)?

  3. The value of \(\rm \frac{(cos\,9^\circ+sin \,81^\circ)(sec\,9^\circ+cosec\,81^\circ)}{cosec^2\,71^\circ+cos^2\,15^\circ-tan^2\,19^\circ+cos^2\,75^\circ} \)  is:

  4. Find the value of sin 4 30° + cos 4 30° - sin 25° cos 65° - sin 65° cos25°.

  5. Find the value of \(cosec(60° + A) - sec(30° - A) +\frac{cosec49^{\circ}}{sec 41^{\circ}}\) .

  6. If sin 6θ + cos 6 θ = \(\frac{1}{3}\) , 0° < θ < 90°, then what is the value of sinθ cosθ? 

  7. (secθ + tan θ )2 + \(\frac{1 + cosec θ}{1 - cosec θ'}\)  0° < θ < 90° is:

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Important Questions from Circular Measure of Angles

  1. If tan 3 θ = cot(θ - 22°), where 3 θ is an angle, find the value of θ.

  2. 1 + tan 15° cot 75° is equal to:

  3. The value of cot (-315°) is :

  4. θ = 135°; γ = 15°.

    What is the value of 2 cos(θ) sin(γ)?

  5. If tan(90 – θ) = \(\frac{2}{\sqrt3}\), then the value of \(2\sqrt3\) tan θ + 1 is:

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