What is the square root of \(15 - 4\sqrt {14} \) ?
The problem asks us to find the square root of the expression \(15 - 4\sqrt {14} \). To do this, we will try to express the number under the square root as a perfect square, specifically in the form \((a-b)^2 = a^2 - 2ab + b^2\).
We need to compare the given expression \(15 - 4\sqrt {14} \) with the form \(a^2 + b^2 - 2ab\).
By comparing, we can see that:
From the second equation, \(2ab = 4\sqrt {14} \), we can divide by 2 to get \(ab = 2\sqrt {14} \).
Now, we need to find two numbers \(a\) and \(b\) such that their product is \(2\sqrt {14} \) and the sum of their squares is \(15\).
Let's consider potential pairs for \(a\) and \(b\) whose product is \(2\sqrt {14}\). We can split the terms: \(2 \times \sqrt{14}\). \(\sqrt{14}\) can be split into \(\sqrt{2} \times \sqrt{7}\).
Possible combinations for \(ab\) could be:
So, we have found the numbers: \(a = 2\sqrt{2}\) and \(b = \sqrt{7}\).
Now we can write the expression \(15 - 4\sqrt{14}\) as a perfect square using these values:
Now, we need to find the square root of this expression:
The square root of a perfect square \((x)^2\) is \(|x|\). So, we need to evaluate \(|2\sqrt{2} - \sqrt{7}|\).
We compare \(2\sqrt{2}\) and \(\sqrt{7}\) by squaring them:
Since \(8 > 7\), it means \(2\sqrt{2} > \sqrt{7}\). Therefore, the expression \(2\sqrt{2} - \sqrt{7}\) is positive.
Thus, the square root is:
The square root of \(15 - 4\sqrt{14}\) is \(2\sqrt{2} - \sqrt{7}\).
| Step | Description | Calculation |
|---|---|---|
| 1 | Identify the form | Compare \(15 - 4\sqrt{14}\) with \(a^2+b^2 - 2ab\) |
| 2 | Equate terms | \(a^2+b^2 = 15\), \(2ab = 4\sqrt{14} \Rightarrow ab = 2\sqrt{14}\) |
| 3 | Find \(a, b\) | Find \(a, b\) such that \(ab = 2\sqrt{14}\) and \(a^2+b^2 = 15\). We found \(a=2\sqrt{2}, b=\sqrt{7}\). |
| 4 | Rewrite the expression | \(15 - 4\sqrt{14} = (2\sqrt{2})^2 + (\sqrt{7})^2 - 2(2\sqrt{2})(\sqrt{7}) = (2\sqrt{2} - \sqrt{7})^2\) |
| 5 | Take the square root | \(\sqrt{(2\sqrt{2} - \sqrt{7})^2} = |2\sqrt{2} - \sqrt{7}|\) |
| 6 | Check sign | \((2\sqrt{2})^2=8\), \((\sqrt{7})^2=7\). Since \(8 > 7\), \(2\sqrt{2} > \sqrt{7}\), so \(2\sqrt{2} - \sqrt{7}\) is positive. |
| 7 | Final result | \(|2\sqrt{2} - \sqrt{7}| = 2\sqrt{2} - \sqrt{7}\) |
| Concept | Description | Formula Example |
|---|---|---|
| Square of a difference | Formula for expanding \((a-b)^2\) | \((a-b)^2 = a^2 - 2ab + b^2\) |
| Simplifying Surds | Rewriting expressions involving square roots in a simpler form. | \(\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2}\) |
| Square root of a perfect square | \(\sqrt{x^2} = |x|\). The absolute value is used because the square root symbol denotes the principal (non-negative) root. | \(\sqrt{(-3)^2} = \sqrt{9} = 3 = |-3|\) |
Surds are expressions containing irrational square roots, like \(\sqrt{2}\) or \(\sqrt{7}\). Simplifying expressions involving surds often requires techniques similar to algebraic manipulation.
One common technique is to recognize or create a perfect square under the square root sign, as we did in this problem. This is particularly useful for expressions of the form \(a \pm \sqrt{b}\) or \(a \pm c\sqrt{d}\).
For an expression \(\sqrt{X \pm Y\sqrt{Z}}\), we often look for two numbers whose sum is \(X\) and whose product is related to \(Y^2 Z\). In our problem, \(X=15\) and \(Y\sqrt{Z} = 4\sqrt{14}\). So we looked for \(a, b\) such that \(a^2+b^2 = 15\) and \(2ab = 4\sqrt{14}\).
This method is a standard approach for denesting square roots of this form.
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