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What is the square root of \(15 - 4\sqrt {14} \) ?

This question was previously asked in
CDS II 2021 General Knowledge Previous Year Paper (14-Nov-2021)
The correct answer is \(2\sqrt 2 - \sqrt 7 \)

Finding the Square Root of \(15 - 4\sqrt {14} \)

The problem asks us to find the square root of the expression \(15 - 4\sqrt {14} \). To do this, we will try to express the number under the square root as a perfect square, specifically in the form \((a-b)^2 = a^2 - 2ab + b^2\).

We need to compare the given expression \(15 - 4\sqrt {14} \) with the form \(a^2 + b^2 - 2ab\).

By comparing, we can see that:

  • The constant term is \(a^2 + b^2 = 15\).
  • The term with the square root is \(2ab = 4\sqrt {14} \).

From the second equation, \(2ab = 4\sqrt {14} \), we can divide by 2 to get \(ab = 2\sqrt {14} \).

Now, we need to find two numbers \(a\) and \(b\) such that their product is \(2\sqrt {14} \) and the sum of their squares is \(15\).

Let's consider potential pairs for \(a\) and \(b\) whose product is \(2\sqrt {14}\). We can split the terms: \(2 \times \sqrt{14}\). \(\sqrt{14}\) can be split into \(\sqrt{2} \times \sqrt{7}\).

Possible combinations for \(ab\) could be:

  • \(a=2\), \(b=\sqrt{14}\): \(a^2+b^2 = 2^2 + (\sqrt{14})^2 = 4 + 14 = 18\). This is not 15.
  • \(a=\sqrt{2}\), \(b=2\sqrt{7}\): \(a^2+b^2 = (\sqrt{2})^2 + (2\sqrt{7})^2 = 2 + (4 \times 7) = 2 + 28 = 30\). This is not 15.
  • \(a=2\sqrt{2}\), \(b=\sqrt{7}\): \(a^2+b^2 = (2\sqrt{2})^2 + (\sqrt{7})^2 = (4 \times 2) + 7 = 8 + 7 = 15\). This matches the required sum of squares.

So, we have found the numbers: \(a = 2\sqrt{2}\) and \(b = \sqrt{7}\).

Now we can write the expression \(15 - 4\sqrt{14}\) as a perfect square using these values:

15 4 14 = 8 + 7 4 14 = ( 2 2 ) 2 + ( 7 ) 2 2 ( 2 2 ) ( 7 ) = ( 2 2 7 ) 2

Now, we need to find the square root of this expression:

15 4 14 = ( 2 2 7 ) 2

The square root of a perfect square \((x)^2\) is \(|x|\). So, we need to evaluate \(|2\sqrt{2} - \sqrt{7}|\).

We compare \(2\sqrt{2}\) and \(\sqrt{7}\) by squaring them:

  • \((2\sqrt{2})^2 = 4 \times 2 = 8\)
  • \((\sqrt{7})^2 = 7\)

Since \(8 > 7\), it means \(2\sqrt{2} > \sqrt{7}\). Therefore, the expression \(2\sqrt{2} - \sqrt{7}\) is positive.

Thus, the square root is:

( 2 2 7 ) 2 = | 2 2 7 | = 2 2 7

The square root of \(15 - 4\sqrt{14}\) is \(2\sqrt{2} - \sqrt{7}\).

Step Description Calculation
1 Identify the form Compare \(15 - 4\sqrt{14}\) with \(a^2+b^2 - 2ab\)
2 Equate terms \(a^2+b^2 = 15\), \(2ab = 4\sqrt{14} \Rightarrow ab = 2\sqrt{14}\)
3 Find \(a, b\) Find \(a, b\) such that \(ab = 2\sqrt{14}\) and \(a^2+b^2 = 15\). We found \(a=2\sqrt{2}, b=\sqrt{7}\).
4 Rewrite the expression \(15 - 4\sqrt{14} = (2\sqrt{2})^2 + (\sqrt{7})^2 - 2(2\sqrt{2})(\sqrt{7}) = (2\sqrt{2} - \sqrt{7})^2\)
5 Take the square root \(\sqrt{(2\sqrt{2} - \sqrt{7})^2} = |2\sqrt{2} - \sqrt{7}|\)
6 Check sign \((2\sqrt{2})^2=8\), \((\sqrt{7})^2=7\). Since \(8 > 7\), \(2\sqrt{2} > \sqrt{7}\), so \(2\sqrt{2} - \sqrt{7}\) is positive.
7 Final result \(|2\sqrt{2} - \sqrt{7}| = 2\sqrt{2} - \sqrt{7}\)

Revision Table: Key Concepts

Concept Description Formula Example
Square of a difference Formula for expanding \((a-b)^2\) \((a-b)^2 = a^2 - 2ab + b^2\)
Simplifying Surds Rewriting expressions involving square roots in a simpler form. \(\sqrt{8} = \sqrt{4 \times 2} = 2\sqrt{2}\)
Square root of a perfect square \(\sqrt{x^2} = |x|\). The absolute value is used because the square root symbol denotes the principal (non-negative) root. \(\sqrt{(-3)^2} = \sqrt{9} = 3 = |-3|\)

Additional Information: Working with Surds

Surds are expressions containing irrational square roots, like \(\sqrt{2}\) or \(\sqrt{7}\). Simplifying expressions involving surds often requires techniques similar to algebraic manipulation.

One common technique is to recognize or create a perfect square under the square root sign, as we did in this problem. This is particularly useful for expressions of the form \(a \pm \sqrt{b}\) or \(a \pm c\sqrt{d}\).

For an expression \(\sqrt{X \pm Y\sqrt{Z}}\), we often look for two numbers whose sum is \(X\) and whose product is related to \(Y^2 Z\). In our problem, \(X=15\) and \(Y\sqrt{Z} = 4\sqrt{14}\). So we looked for \(a, b\) such that \(a^2+b^2 = 15\) and \(2ab = 4\sqrt{14}\).

This method is a standard approach for denesting square roots of this form.

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Important Questions from Surds and Indices

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  3. If √625 = 25; then√(.00000625/25)is:

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    C. 0.0001

    D. 0.0005
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