The objective is to determine the smallest integer that needs to be added to 2378 to obtain a perfect square.
First, calculate the square root of the number 2378.
$ \sqrt{2378} \approx 48.76 $
To find the next perfect square, we consider the integer immediately following 48.76, which is 49.
Now, calculate the square of 49:
$ 49^2 = 2401 $
Thus, 2401 is the smallest perfect square that is greater than 2378.
The smallest number that must be added is the difference between this larger perfect square (2401) and the original number (2378).
Number to add $= 2401 - 2378 $
Number to add $= 23 $
Adding 23 to 2378 results in 2401, which is a perfect square ($49^2$). Therefore, the smallest number required is 23.
In the following examples, a number is coded as three digits — representing the remainders when the number is divided by 3, 7, and 11, respectively.
Example 1: $53 \rightarrow 53 \div 3 = 17 \text{ R} 2$, $53 \div 7 = 7 \text{ R } 4$, $53 \div 11 = 4 \text{ R } 9 \rightarrow \text{ Code: } 2, 4, 9$
Example 2: $68 \rightarrow 68 \div 3 = 22 \text{ R} 2$, $68 \div 7 = 9 \text{ R } 5$, $68 \div 11 = 6 \text{ R } 2 \rightarrow \text{ Code: } 2, 5, 2$
By following this method, which is the least number which would have the code - 2, 2, 2?
Which of the following statement is TRUE for Whole Numbers?
What is the Highest Common Factor of 2 3× 3 5and 3 3× 5 2?
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